问题描述
我有几个单选按钮组，当它们被选中时我需要运行一个脚本.
我使用以下脚本来检查其中一个是否被选中，如果没有，则对其进行着色.
如何编写代码，以便在检查所有单选按钮组后，运行脚本.
检查单选按钮组是否被选中的代码:
$('.aQuestion').each(function(){if($(this).find('input[type="radio"]:checked').length > 0){警报(检查")；}别的{警报(未检查")；}});单选按钮组(大约有 90 个):
提前致谢:D
解决方案 假设每个问题只有一个单选按钮组，您不需要迭代问题以找出它们都被选中:
p>
var $questions = $(".aQuestion");if($questions.find("input:radio:checked").length === $questions.length) {//全部检查}
jsFiddle 演示了上述内容.
I have several radiobuttongroups, and I need to run a script when they are checked.
I use the following script to check if one of them is checked, if not, then color it.
How can I make the code, so that when all of the radiobuttongroups are checked, then run script.
The code that checks if the radiobuttongroups are checked:
$('.aQuestion').each(function(){
if($(this).find('input[type="radio"]:checked').length > 0)
{
alert("checked");
}
else
{
alert("not checked");
}
});
The radiobuttongroups (there is about 90 of them):
<div class='aQuestion' id='div1'>
<STRONG>1. </STRONG>
<STRONG>Question</STRONG></br>
<INPUT TYPE='radio' NAME='grp1' VALUE='0'>answer 1</br>
<INPUT TYPE='radio' NAME='grp1' VALUE='1'>answer 2</br>
<INPUT TYPE='radio' NAME='grp1' VALUE='2'>answer 3</br>
<INPUT TYPE='radio' NAME='grp1' VALUE='3'>answer 4</br>
<INPUT TYPE='radio' NAME='grp1' VALUE='4'>answer 5
</div>
<div class='aQuestion' id='div2'>
<STRONG>2. </STRONG>
<STRONG>Question</STRONG></br>
<INPUT TYPE='radio' NAME='grp2' VALUE='0'>answer 1</br>
<INPUT TYPE='radio' NAME='grp2' VALUE='1'>answer 2</br>
<INPUT TYPE='radio' NAME='grp2' VALUE='2'>answer 3</br>
<INPUT TYPE='radio' NAME='grp2' VALUE='3'>answer 4</br>
<INPUT TYPE='radio' NAME='grp2' VALUE='4'>answer 5
</div>
Thanks in advance :D
解决方案 Assuming there is only one radio button group per question, you don't need to iterate the questions in order to find out they're all selected:
var $questions = $(".aQuestion");
if($questions.find("input:radio:checked").length === $questions.length) {
// All Checked
}
jsFiddle which demonstrates the above.
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