问题描述

我想创建一个文件资源管理器，但在id=tree.int()方面遇到了一些问题

def SUBS(path):
    PO   = ""
    parent = tree.parent(XOM)
    while os.path.exists(path+"/"+PO):
          X1   = 0
          List = os.listdir(path+"/"+PO)
          for element in List:
              X1 += 1
              if os.path.isfile(path+"/"+element):
                 tree.insert(XOM,str(X1),text=element)
              if os.path.isdir(path+"/"+element):
                 id = tree.insert(XOM,str(X1),text=element)
                 PO = element
          break
X    = 0
Path = "/"
WinT = Tk()
tree = ttk.Treeview(WinT ,height=15)
tree.pack(expand=YES,fill=BOTH)
tree.heading("#0" ,text="Directory")

PATH = os.listdir(Path)
for element in PATH:
    X  += 1
    PaTh = Path+"/"+element
    if "//" in PaTh:
       PATH = PaTh.replace('//','/')
    if "//" not in PaTh:
       PATH = PaTh
    if "." in element :
       tree.insert('',str(X),text=element)
    if "." not in element:
       XOM = tree.insert('',str(X),text=element)
       SUBS(PATH)

推荐答案

您想要的是递归函数，即调用自身的函数。

def SUBS(path, parent):    
    for p in os.listdir(path):
        abspath = os.path.join(path, p)
        parent_element = tree.insert(parent, 'end', text=p, open=True)
        if os.path.isdir(abspath):
            SUBS(abspath, parent_element)


path = "C:/"
WinT = Tk()
tree = ttk.Treeview(WinT ,height=15)
tree.pack(expand=YES,fill=BOTH)
tree.heading("#0" ,text="Directory")
root = tree.insert('', 'end', text=path, open=True)
SUBS(path, root)
WinT.mainloop()

它获取目录中的所有元素并将其添加到树小部件。如果它是函数本身调用的另一个目录，直到它们不再是剩余的目录。

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