本文介绍了如何透视表?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的表有这个结构
subcode date rol1 rol2 rol3 rol4 rol5 rol6 upto rol60
--------------------------------------------------------------
mc1603 12/03/2011 p p a p p p a
mc1604 12/03/2011 p p a p p p a
mc1605 12/03/2011 p p a p p p a
mc1606 12/03/2011 p p a p p p a
这里
p=present
a=absent
这张表会变成
rollno mc1603 mc1604 mc1605 mc1606 date
-------------------------------------------------
rol1 p p p p 12/03/2011
rol2 p p p p 12/03/2011
rol3 p p a p 12/03/2011
推荐答案
下面是你如何使用 unpivot
和 pivot
来做到这一点:
Here is how you would do this with both an unpivot
and then pivot
:
静态查询:
create table #temp
(
subcode varchar(50),
date smalldatetime,
rol1 varchar(1),
rol2 varchar(1),
rol3 varchar(1),
rol4 varchar(1),
rol5 varchar(1),
rol6 varchar(1),
rol60 varchar(1)
)
insert into #temp values('mc1603', '03/12/2011', 'p', 'p', 'a', 'p', 'p', 'p', 'a')
insert into #temp values('mc1604', '03/12/2011', 'p', 'p', 'a', 'p', 'p', 'p', 'a')
insert into #temp values('mc1605', '03/12/2011', 'p', 'p', 'a', 'p', 'p', 'p', 'a')
insert into #temp values('mc1606', '03/12/2011', 'p', 'p', 'a', 'p', 'p', 'p', 'a')
SELECT p.rollNo, p.[mc1603], p.[mc1604], p.[mc1605], p.[mc1606], p.date
FROM
(
SELECT *
FROM
(
select subcode, date, rol1, rol2, rol3, rol4, rol5, rol6, rol60
from #temp
) x
UNPIVOT
(
presence FOR rollNo IN([rol1], [rol2], [rol3], [rol4], [rol5], [rol6], [rol60])
) unpiv
) x
PIVOT
(
max(presence)
FOR subcode IN([mc1603], [mc1604], [mc1605], [mc1606])
) p
drop table #temp
您也可以使用 Dynamic SQL 执行此操作,但您需要获取列列表首先在你可以 unpivot
然后 pivot
:
You can also do this with Dynamic SQL but you will need to get the list of columns first before you can unpivot
and then pivot
:
动态查询:
-- get your roll no columns
DECLARE @cols AS VARCHAR(MAX),
@query AS VARCHAR(MAX);
SET @cols = STUFF((SELECT ',' + QUOTENAME(c.Name)
FROM sys.columns c
WHERE OBJECT_ID = OBJECT_ID('dbo.temp') AND c.NAME LIKE 'rol%'
FOR XML PATH(''), TYPE
).value('.', 'VARCHAR(MAX)')
,1,1,'')
-- get your dynamic string
set @query = 'SELECT p.rollNo, p.[mc1603], p.[mc1604], p.[mc1605], p.[mc1606], p.date
FROM
(
SELECT *
FROM
(
select subcode, date, ' + @cols + '
from temp
) x
UNPIVOT
(
presence FOR rollNo IN(' + @cols + ')
) unpiv
) x
PIVOT
(
max(presence)
FOR subcode IN([mc1603], [mc1604], [mc1605], [mc1606])
) p'
exec(@query)
结果:
rol1 p p p p 2011-03-12 00:00:00
rol2 p p p p 2011-03-12 00:00:00
rol3 a a a a 2011-03-12 00:00:00
rol4 p p p p 2011-03-12 00:00:00
rol5 p p p p 2011-03-12 00:00:00
rol6 p p p p 2011-03-12 00:00:00
rol60 a a a a 2011-03-12 00:00:00
这篇关于如何透视表?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除!