问题描述
I have 2 tables like below
location_distance
----------------------------------------------
id | fromLocid | toLocid | distance
----------------------------------------------
1 | 3 | 5 | 70
2 | 6 | 8 | 15
3 | 2 | 4 | 63
...
other_table
--------------------------------------------
Id | fromLocid | toLocid | otherdata
--------------------------------------------
12 | 5 | 3 | xxxx
22 | 2 | 4 | xxxx
56 | 8 | 6 | xxxx
78 | 3 | 5 | xxxx
I would like to retrieve the distance b/w the locations in other_table for each row. Here's what i've tried
SELECT ot.*, ld.distance FROM other_table AS ot
INNER JOIN location_distance ld ON ld.fromLocid = ot.fromLocid AND ld.toLocid = ot.toLocid
This doesnt return the rows if the locations values are vice versa. How can i rewrite the above query to produce expected result? Should i inlude OR condition on the join clause? like below?
SELECT ot.*, ld.distance FROM other_table AS ot
INNER JOIN location_distance ld ON (ld.fromLocid = ot.fromLocid OR ld.fromLocid = ot.toLocid) AND (ld.toLocid = ot.fromLocid OR ld.toLocid = ot.fromLocid)
but this query Explain says "Range checked for each record". .. is this a bad practise?
Result
--------------------------------------------------------
Id | fromLocid | toLocid | otherdata | distance
--------------------------------------------------------
22 | 2 | 4 | xxxx | 63
78 | 3 | 5 | xxxx | 70
Expected Result should be
-----------------------------------------------------
Id | fromLocid | toLocid | otherdata | distance
-----------------------------------------------------
12 | 5 | 3 | xxxx | 70
22 | 2 | 4 | xxxx | 63
56 | 8 | 6 | xxxx | 15
78 | 3 | 5 | xxxx | 70
You can join on the location_distance
table twice using a LEFT JOIN
and then use the COALESCE()
function to return the correct value for the distance
:
select ot.id,
ot.fromlocid,
ot.tolocid,
ot.otherdata,
coalesce(ld1.distance, ld2.distance) distance
from other_table ot
left join location_distance ld1
on ld1.fromLocid = ot.toLocid
and ld1.toLocid = ot.fromLocid
left join location_distance ld2
on ld2.toLocid = ot.toLocid
and ld2.fromLocid = ot.fromLocid
See SQL Fiddle with Demo
This returns the result:
| ID | FROMLOCID | TOLOCID | OTHERDATA | DISTANCE |
---------------------------------------------------
| 12 | 5 | 3 | xxxx | 70 |
| 22 | 2 | 4 | xxxx | 63 |
| 56 | 8 | 6 | xxxx | 15 |
| 78 | 3 | 5 | xxxx | 70 |
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