XMLHttpRequest 抛出 InvalidSateError 说“必须打开对象状态";

XMLHttpRequest throwing InvalidSateError saying quot;Object state must be openedquot;(XMLHttpRequest 抛出 InvalidSateError 说“必须打开对象状态;)
本文介绍了XMLHttpRequest 抛出 InvalidSateError 说“必须打开对象状态";的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

代码 -

"use strict";

var AJAX = function (params) {
    this.server ={};
    this.url = params.url;
    this.method = params.method;
    this.dataType = params.dataType;
    this.formData = params.formData;

    this.init = function(){
        if(typeof XMLHttpRequest != 'undefined'){
            this.server = new XMLHttpRequest();
            this.server.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
            this.server.setRequestHeader('Content-length', this.formData.length);
            this.server.setRequestHeader('Connection', 'close');
            console.log("XMLHttpRequest created.");
            return true;
        }
    };

    this.send = function(){
        if(this.init()){
            this.server.open(this.method, this.url, true);
            this.server.send(this.formData);
        }
    };

};

它抛出以下错误:

Error in event handler for contextMenus: InvalidStateError: Failed to execute 'setRequestHeader' on 'XMLHttpRequest': The object's state must be OPENED.

如何使用 -

var data = new FormData();

data.append('user', 'sachin');
var params = {
    url : 'example.com',
    method : 'post',
    dataType: 'json',
    formData : data
};

var backgroundWindow = chrome.extension.getBackgroundPage();

var ajax = new backgroundWindow.AJAX(params);

ajax.send();

我似乎无法弄清楚背后的原因.

I can't seem to figure out what's the reason behind.

推荐答案

错误是直截了当的:

contextMenus 的事件处理程序出错:InvalidStateError:无法在XMLHttpRequest"上执行setRequestHeader":对象的状态必须是 OPENED.

Error in event handler for contextMenus: InvalidStateError: Failed to execute 'setRequestHeader' on 'XMLHttpRequest': The object's state must be OPENED.

你需要在设置请求头之前调用.open(..).

You need to call .open(..) before setting the request headers.

鉴于您的代码,我相信最好的方法是将调用移动到 init(..) 函数中的 open .

Given your code, I believe the best way would be to move the call to open in the init(..) function.

var AJAX = function (params) {
    this.server ={};
    this.url = params.url;
    this.method = params.method;
    this.dataType = params.dataType;
    this.formData = params.formData;

    this.init = function(){
        if(typeof XMLHttpRequest != 'undefined'){
            this.server = new XMLHttpRequest();

            //Open first, before setting the request headers.
            this.server.open(this.method, this.url, true);

            //Now set the request headers.
            this.server.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
            //this.server.setRequestHeader('Content-length', this.formData.length);
            //this.server.setRequestHeader('Connection', 'close');
            console.log("XMLHttpRequest created.");
            return true;
        }
    };

    this.send = function(){
        if(this.init()){
            this.server.send(this.formData);
        }
    };

};

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