本文介绍了如何编写带有回调的 jQuery 函数?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有以下功能:
function loadProjects(pID) {
$.ajax({
url: myURL,
success: function (dataJS) {XXXXXXXXXXXXXXXX}
});
}
我像这样调用这个函数 loadProjects(1);
I call this function like so loadProjects(1);
问题是我希望能够在成功后定义一个回调函数，并且我想在我做 loadProjects(1, callback:{whatever js is included here gets call back after success})的时候包含它
Issue is I want to be able to define a callBack function after success, and I'd like to include it when I do loadProjects(1, callback:{whatever js is included here gets called back after success})
如何让函数接受回调?如何将回调传递给该函数?
How can I have a function accept a callback? How can I pass a callback to that function?
谢谢
推荐答案
function loadProjects(pID, callbackFunction)
{
$.ajax({
url: myURL,
success: function (dataJS)
{
if(typeof callbackFunction == 'function')
{
callbackFunction.call(this, dataJS);
}
}
});
}
用法:
loadProjects(pID, function(dataJS)
{
// do stuff with your dataJS, bear in mind you can call the parameter any name.
});
这篇关于如何编写带有回调的 jQuery 函数?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除！