问题描述

我正在使用 Jasmine 测试我的 Angular 应用程序并希望监视一个匿名函数.使用 angular-notify 服务 https://github.com/cgross/angular-notify，我想要知道通知函数是否被调用.

I'm using Jasmine to test my angular application and want to spy on an anonymous function. Using angular-notify service https://github.com/cgross/angular-notify, I want to know whether notify function have been called or not.

这是我的控制器:

angular.module('module').controller('MyCtrl', function($scope, MyService, notify) {

  $scope.isValid = function(obj) {
    if (!MyService.isNameValid(obj.name)) {
      notify({ message:'Name not valid', classes: ['alert'] });
      return false;
    }
  }
});

这是我的测试:

'use strict';

describe('Test MyCtrl', function () {
  var scope, $location, createController, controller, notify;

  beforeEach(module('module'));

  beforeEach(inject(function ($rootScope, $controller, _$location_, _notify_) {
    $location = _$location_;
    scope = $rootScope.$new();
    notify = _notify_;

    notify = jasmine.createSpy('spy').andReturn('test');

    createController = function() {
      return $controller('MyCtrl', {
        '$scope': scope
      });
    };
  }));

  it('should call notify', function() {
    spyOn(notify);
    controller = createController();
    scope.isValid('name');
    expect(notify).toHaveBeenCalled();
  });
});

一个明显的回报:

Error: No method name supplied on 'spyOn(notify)'

因为它应该是类似 spyOn(notify, 'method') 的东西，但是由于它是一个匿名函数，所以它没有任何方法.

Because it should be something like spyOn(notify, 'method'), but as it's an anonymous function, it doesn't have any method.

感谢您的帮助.

推荐答案

Daniel Smink 的答案是正确的，但请注意 Jasmine 2.0 的语法已更改.

Daniel Smink's answer is correct, but note that the syntax has changed for Jasmine 2.0.

notify = jasmine.createSpy().and.callFake(function() {
  return false;
});

如果您只需要一个简单的实现，我还发现直接返回响应很有用

I also found it useful to just directly return a response if you only need a simple implementation

notify = jasmine.createSpy().and.returnValue(false);

这篇关于如何使用 Jasmine 监视匿名函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！