本文介绍了 pandas Groupby：创建两列的Groupby时，如何按正确的顺序对工作日进行排序？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
以下数据框包含一年中每小时的值(千瓦时)。
cons2016.head()
Date Hour kWh Month Weekday
0 2016-01-01 00:00 71.48 January Friday
1 2016-01-01 01:00 65.32 January Friday
2 2016-01-01 02:00 65.38 January Friday
3 2016-01-01 03:00 62.44 January Friday
4 2016-01-01 04:00 57.56 January Friday
我要根据此数据帧(按垂直轴上的工作日和水平轴上的小时数的正确顺序)创建一个Seborn热图。所以我分组：
weekdayhour = cons2016.groupby(["Weekday", "Hour"]).mean()
weekdayhour = weekdayhour.reset_index()
weekdayhour.head()
Weekday Hour kWh
0 Friday 00:00 61.188113
1 Friday 01:00 57.231698
2 Friday 02:00 55.818679
3 Friday 03:00 55.074151
4 Friday 04:00 55.049811
但现在工作日按字母顺序(也在热图中)：
heat_weekdayhour = weekdayhour.pivot(index="Weekday", columns="Hour", values="kWh")
sns.heatmap(heat_weekdayhour)
我如何才能按正常顺序安排工作日，从星期一到星期日？我尝试按如下方式添加.reindex：
weekdays = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"]
weekdayhour = cons2016.groupby(["Weekday", "Hour"]).mean().reindex(labels=weekdays)
但这给了我TypeError: Expected tuple, got str
感谢您的帮助！
推荐答案
使用Categorical
weekdays = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"]
weekdayhour.Weekday = pd.Categorical(weekdayhour.Weekday,categories=weekdays)
weekdayhour = weekdayhour.sort_values('Weekday')
Weekday Hour kWh
0 Friday 00:00 71.48
1 Friday 01:00 65.32
2 Friday 02:00 65.38
3 Friday 03:00 62.44
4 Friday 04:00 57.56
更多信息：
weekdayhour.Weekday
0 Friday
1 Friday
2 Friday
3 Friday
4 Friday
Name: Weekday, dtype: category
Categories (7, object): [Monday < Tuesday < Wednesday < Thursday < Friday < Saturday < Sunday]
这篇关于 pandas Groupby：创建两列的Groupby时，如何按正确的顺序对工作日进行排序？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除！