本文介绍了未并行处理的Python线程的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是Python的中间人,我想以并行模式运行几个相同的类实例,用于获取数据和为金融市场做出决策。为了继续我的想法,我运行下面的代码来看看Python是如何工作的,它似乎可以运行一次完整的第一类实例和第二类实例,我想并行运行它,我如何才能...? 以下是用于测试的一些示例代码..
import threading
import time
class thr(object):
def __init__(self, name):
self.name = name
self.x = 0
def run(self):
for i in list(range(10)):
self.x +=1
print("something {0} {1}".format(self.name, self.x))
time.sleep(1)
F = thr("First")
S = thr("Second")
threading.Thread(target=F.run())
threading.Thread(target=S.run())
和结果如下...
something First 1
something First 2
something First 3
something First 4
something First 5
something First 6
something First 7
something First 8
something First 9
something First 10
something Second 1
something Second 2
something Second 3
something Second 4
something Second 5
something Second 6
something Second 7
something Second 8
something Second 9
something Second 10
Out[27]: <Thread(Thread-25, initial)>
推荐答案
问题在这里:
threading.Thread(target=F.run())
threading.Thread(target=S.run())
target=
接受可调用对象或None
。F.run()
立即执行F.run
,等待其完成,然后传递返回值(run()
方法中的None
)作为目标。
您想要这样的内容:
t1 = threading.Thread(target=F.run)
t2 = threading.Thread(target=S.run)
t1.start()
t2.start()
请注意,run
后面没有括号
以下是带有建议更改的完整程序:
import threading
import time
class thr(object):
def __init__(self, name):
self.name = name
self.x = 0
def run(self):
for i in list(range(10)):
self.x +=1
print("something {0} {1}".format(self.name, self.x))
time.sleep(1)
F = thr("First")
S = thr("Second")
t1 = threading.Thread(target=F.run)
t2 = threading.Thread(target=S.run)
t1.start()
t2.start()
和输出(Python3.6.1):
$ python sf.py
something First 1
something Second 1
something Second 2
something First 2
something Second 3
something First 3
something Second 4
something First 4
something Second 5
something First 5
something Second 6
something First 6
something Second 7
something First 7
something First 8
something Second 8
something First 9
something Second 9
something First 10
something Second 10
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