本文介绍了如何同时移动多只乌龟?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的任务是在一条赛道上放置两只乌龟(大小相同但不同的赛道)。我可以让它们移动,但第二个只有当第一个移动了半条赛道时才能移动。我不知道如何让乌龟同时移动。以下是我的代码:
import turtle
import random
import time
wn = turtle.Screen()
wn.bgcolor("lightgreen")
t = turtle.Turtle()
t.shape('turtle')
t.color('red')
t2 = turtle.Turtle()
t2.shape('turtle')
t2.color('blue')
#user input function
p = float(input('please insert the perimeter:'))
#set the track
def drawTrack(p,r):
shortside = (p/2.0)/(r+1)
longside = r*shortside
turtle.setup((shortside*2)+60, longside +40)
t.penup()
t2.penup()
t.setposition(-shortside-10, -longside/2)
t2.setposition(10, -longside/2)
for i in range (2):
#first track
t.speed(1)
t.pendown()
t.forward(shortside)
t.left(90)
t.forward(longside)
t.left(90)
#second track
t2.speed(1)
t2.pendown()
t2.forward(shortside)
t2.left(90)
t2.forward(longside)
t2.left(90)
drawTrack(p,2)
wn.exitonclick()
推荐答案
我让每只乌龟重复移动一个微小的增量,这样它们之间的最大间隔就只有1个像素:
# Setup
import turtle
screen = turtle.Screen()
screen.bgcolor("white")
screen.title("Turtle Movement")
screen.setup(width=500, height=500)
# Object 1 set up
obj1 = turtle.Turtle()
obj1.color("red") # Sets obj1's colour
obj1.speed(0) # The drawing speed will go as fast as it can if it is set to zero
obj1.penup() # Don't want it to draw a line as I goes to 0, -50
obj1.goto(0, -50) # goes to 0, -50
obj1.pendown() # Now we want it to draw
# Object 2 set up
obj2 = turtle.Turtle()
obj2.color("blue") # sets obj2's colour
obj2.speed(0) # The drawing speed will go as fast as it can if it is set to zero
obj2.penup() # Don't want it to draw a line as I goes to 0, -50
obj2.goto(0, 50) # goes to 0, 50
obj2.pendown() # Now we want it to draw
# Movement of objects
while True: # infinite loop
obj1.forward(1) # Moves obj1 forwards by 1
obj2.forward(1) # Moves obj2 forwards by 1
注意:
移动量越小,
例如forward(Movement amount is in here)
,
动作越流畅,速度就会越慢。
我鼓励你调整价值观,尝试一下!
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