问题描述

我有如下所示的数据帧

stud_name   act_qtr year    yr_qty  qtr mov_avg_full    mov_avg_2qtr_min_period
0   ABC Q2  2014    2014Q2  NaN NaN NaN
1   ABC Q1  2016    2016Q1  Q1  13.0    14.5
2   ABC Q4  2016    2016Q4  NaN NaN NaN
3   ABC Q4  2017    2017Q4  NaN NaN NaN
4   ABC Q4  2020    2020Q4  NaN NaN NaN

OP = pd.read_clipboard()

stud_name   qtr year    t_score p_score yr_qty  mov_avg_full    mov_avg_2qtr_min_period
0   ABC Q1  2014    10  11  2014Q1  10.000000   10.0
1   ABC Q1  2015    11  32  2015Q1  10.500000   10.5
2   ABC Q2  2015    13  45  2015Q2  11.333333   12.0
3   ABC Q3  2015    15  32  2015Q3  12.250000   14.0
4   ABC Q4  2015    17  21  2015Q4  13.200000   16.0
5   ABC Q1  2016    12  56  2016Q1  13.000000   14.5
6   ABC Q2  2017    312 87  2017Q2  55.714286   162.0
7   ABC Q3  2018    24  90  2018Q3  51.750000   168.0

df = pd.read_clipboard()

我想根据以下逻辑填充na()

例如：让我们取stud_name = ABC。他有多项犯罪记录。让我们将他的NA作为2020Q4。为了填补这一空白，我们从df中选取stud_name=ABC之前的最新记录(即2018Q3)。同样，如果我们取stud_name = ABC。他的另一张NA唱片是2014Q2。我们从df中选取stud_name=ABC之前(即2014Q1)的最新(先前)记录。我们需要根据yearqty值进行排序，以正确获取最新(先前)记录

我们需要为每个stud_name和大型数据集执行此操作

因此，我们填充mov_avg_full和mov_avg_2qtr_min_period

如果在df数据帧中没有要查看的以前的记录，则将NA保留为原样

我正在尝试下面这样的方法，但它不起作用，而且不正确

Filled = OP.merge(df,on=['stud_name'],how='left')
filled.sort_values(['year','Qty'],inplace=True)
filled['mov_avg_full'].fillna(Filled.groupby('stud_name']['mov_avg_full'].shift())
filled['mov_avg_2qtr_min_period'].fillna(Filled .groupby('stud_name']['mov_avg_2qtr_min_period'].shift())

我希望我的输出如下所示

推荐答案

在这种情况下，您可能希望使用append而不是merge。换句话说，您希望垂直连接，而不是水平连接。然后在按stud_name和yr_qtr对DataFrame进行排序后，可以对其使用groupby和fillna方法。

代码：

import pandas as pd

# Create the sample dataframes
import numpy as np
op = pd.DataFrame({'stud_name': {0: 'ABC', 1: 'ABC', 2: 'ABC', 3: 'ABC', 4: 'ABC'}, 'act_qtr': {0: 'Q2', 1: 'Q1', 2: 'Q4', 3: 'Q4', 4: 'Q4'}, 'year': {0: 2014, 1: 2016, 2: 2016, 3: 2017, 4: 2020}, 'yr_qty': {0: '2014Q2', 1: '2016Q1', 2: '2016Q4', 3: '2017Q4', 4: '2020Q4'}, 'qtr': {0: np.NaN, 1: 'Q1', 2: np.NaN, 3: np.NaN, 4: np.NaN}, 'mov_avg_full': {0: np.NaN, 1: 13.0, 2: np.NaN, 3: np.NaN, 4: np.NaN}, 'mov_avg_2qtr_min_period': {0: np.NaN, 1: 14.5, 2: np.NaN, 3: np.NaN, 4: np.NaN}})
df = pd.DataFrame({'stud_name': {0: 'ABC', 1: 'ABC', 2: 'ABC', 3: 'ABC', 4: 'ABC', 5: 'ABC', 6: 'ABC', 7: 'ABC'}, 'qtr': {0: 'Q1', 1: 'Q1', 2: 'Q2', 3: 'Q3', 4: 'Q4', 5: 'Q1', 6: 'Q2', 7: 'Q3'}, 'year': {0: 2014, 1: 2015, 2: 2015, 3: 2015, 4: 2015, 5: 2016, 6: 2017, 7: 2018}, 't_score': {0: 10, 1: 11, 2: 13, 3: 15, 4: 17, 5: 12, 6: 312, 7: 24}, 'p_score': {0: 11, 1: 32, 2: 45, 3: 32, 4: 21, 5: 56, 6: 87, 7: 90}, 'yr_qty': {0: '2014Q1', 1: '2015Q1', 2: '2015Q2', 3: '2015Q3', 4: '2015Q4', 5: '2016Q1', 6: '2017Q2', 7: '2018Q3'}, 'mov_avg_full': {0: 10.0, 1: 10.5, 2: 11.333333, 3: 12.25, 4: 13.2, 5: 13.0, 6: 55.714286, 7: 51.75}, 'mov_avg_2qtr_min_period': {0: 10.0, 1: 10.5, 2: 12.0, 3: 14.0, 4: 16.0, 5: 14.5, 6: 162.0, 7: 168.0}})

# Append df to op
dfa = op.append(df[['stud_name', 'yr_qty', 'mov_avg_full', 'mov_avg_2qtr_min_period']])

# Sort before applying fillna
dfa = dfa.sort_values(['stud_name', 'yr_qty'])

# Group by stud_name and apply ffill
dfa[['mov_avg_full', 'mov_avg_2qtr_min_period']] = dfa.groupby('stud_name')[['mov_avg_full', 'mov_avg_2qtr_min_period']].fillna(method='ffill')

# Extract the orginal rows from op and deal with columns
dfa = dfa[dfa.act_qtr.notna()].drop('qtr', axis=1)

print(dfa)

输出：

这篇关于大 pandas 填充NA，但并不都是基于最近的记录的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！