问题描述
import os
import subprocess
proc = subprocess.Popen(['ls','*.bc'], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
out,err = proc.communicate()
print out
这个脚本应该打印所有带有 .bc 后缀的文件，但是它返回一个空列表.如果我在命令行中手动执行 ls *.bc ，它就可以工作.在脚本中执行 ['ls','test.bc'] 也可以，但由于某种原因星号不起作用.. 有什么想法吗?
This script should print all the files with .bc suffix however it returns an empty list. If I do ls *.bc manually in the command line it works. Doing ['ls','test.bc'] inside the script works as well but for some reason the star symbol doesnt work.. Any ideas ?
推荐答案
您需要提供 shell=True 以通过 shell 解释器执行命令.但是，如果您这样做，则不能再提供一个列表作为第一个参数，因为这些参数将被引用.相反，请指定您希望将其传递给 shell 的原始命令行:
You need to supply shell=True to execute the command through a shell interpreter.
If you do that however, you can no longer supply a list as the first argument, because the arguments will get quoted then. Instead, specify the raw commandline as you want it to be passed to the shell:
proc = subprocess.Popen('ls *.bc', shell=True,
stdout=subprocess.PIPE,
stderr=subprocess.PIPE)
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