本文介绍了Python中子进程读取线超时的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有一个小问题，我不太确定如何解决.这是一个最小的例子:
I have a small issue that I'm not quite sure how to solve. Here is a minimal example:
scan_process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
while(some_criterium):
line = scan_process.stdout.readline()
some_criterium = do_something(line)
我想要什么
scan_process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
while(some_criterium):
line = scan_process.stdout.readline()
if nothing_happens_after_10s:
break
else:
some_criterium = do_something(line)
我从子进程中读取了一行并对其进行了处理.如果在固定时间间隔后没有线路到达，我该如何退出?
I read a line from a subprocess and do something with it. How can I exit if no line arrived after a fixed time interval?
推荐答案
感谢大家的回答！
我找到了一种方法来解决我的问题，只需使用 select.poll 来查看标准输出.
I found a way to solve my problem by simply using select.poll to peek into standard output.
import select
...
scan_process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
poll_obj = select.poll()
poll_obj.register(scan_process.stdout, select.POLLIN)
while(some_criterium and not time_limit):
poll_result = poll_obj.poll(0)
if poll_result:
line = scan_process.stdout.readline()
some_criterium = do_something(line)
update(time_limit)
这篇关于Python中子进程读取线超时的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除！