问题描述
我正在查看这个问题.
就我而言，我想做一个:
In my case, I want to do a :
import subprocess
p = subprocess.Popen(['ls', 'folder/*.txt'], stdout=subprocess.PIPE,
stderr=subprocess.PIPE)
out, err = p.communicate()
现在我可以在命令行上检查执行ls 文件夹/*.txt"是否有效，因为该文件夹有许多 .txt 文件.
Now I can check on the commandline that doing a "ls folder/*.txt" works, as the folder has many .txt files.
但在 Python (2.6) 中我得到:
But in Python (2.6) I get:
ls: 无法访问 * : 没有这样的文件或目录
我尝试过这样做:r'文件夹/*.txt'r"文件夹/*.txt"r'文件夹/\*.txt'和其他变体，但似乎 Popen 根本不喜欢 * 字符.
I have tried doing:
r'folder/*.txt'
r"folder/*.txt"
r'folder/\*.txt'
and other variations, but it seems Popen does not like the * character at all.
还有其他方法可以逃脱*吗?
Is there any other way to escape *?
推荐答案
*.txt会被你的shell自动扩展成file1.txt file2.txt ....如果引用*.txt，则不起作用:
*.txt is expanded by your shell into file1.txt file2.txt ... automatically. If you quote *.txt, it doesn't work:
[~] ls "*.py"
ls: cannot access *.py: No such file or directory
[~] ls *.py
file1.py file2.py file3.py
如果您想获取与您的模式匹配的文件，请使用 glob:
If you want to get files that match your pattern, use glob:
>>> import glob
>>> glob.glob('/etc/r*.conf')
['/etc/request-key.conf', '/etc/resolv.conf', '/etc/rc.conf']
这篇关于Python 子进程 Popen:为什么会出现“ls *.txt"?不行?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！