问题描述

我基本上想做的是以下几点:

What I basically want to do is the following:

import threading
import Queue

def test_thread(elem, q):
    q.put(elem ** 2)

a = [1,2,3,4,5,6,7,8]
q = Queue.Queue()
results = []
for x in range(8):
    print x
    threading.Thread(target=test_thread, args=(a[x], q)).start()
    results.append(q.get())

但不是一次运行所有线程，我只想并行运行 2 个线程并迭代列表.一旦一个线程完成，就应该处理列表中的下一个值.我找不到示例，也不确定如何为此构建循环.

But instead of running all threads at once I want to run only say 2 in parallel adn iterate over the list. Once one thread is done the next value from the list should be processed. I could't find an example and I am not sure how to construct the loops for this.

另外，我不明白队列的行为.我本来希望所有平方数都在队列中.但相反，只有一个值?(上面的代码已更改为将所有结果存储在结果"中).非常感谢提示、评论、关键字.

In addition, I do not understand the behavior of the Queue. I would have expected that ALL squared numbers are in the queue. But instead there is only one value? (The code above has changed to store all results in "results"). Hints, comments, keywords are highly appreciated.

第二个问题:

抱歉，我以为 q.get() 会返回所有结果.但它只是像时尚一样给出队列中的元素.

Sorry, I thought q.get() will return all the results. But it just gives the elements in a queue like fashion.

推荐答案

你可以为此使用线程池:

You can use a thread pool for this:

import threading
from multiprocessing.pool import ThreadPool

def test_thread(elem):
    return elem ** 2

a = [1,2,3,4,5,6,7,8]
pool = ThreadPool(2) # 2 worker threads
results = []
for x in range(8):
    print x
    results.append(pool.apply_async(test_thread, args=(a[x],)))

results = [result.get() for result in results]
# You can also replace this for loop altogether using pool.map
# and get the same result:
# results = pool.map(test_thread, range(8))
print(results)

输出:

0
1
2
3
4
5
6
7
[1, 4, 9, 16, 25, 36, 49, 64]

ThreadPool 类是 <代码>多处理模块.它也可以通过 multiprocessing.dummy.Pool.它允许您创建一个线程池来处理任意数量的工作项，同时始终将同时处理的工作项的数量限制为您指定的数量.您可以使用普通 multiprocessing.Pool 来了解它的 API.完全一样，只是到处都是进程"，你用线程"替换它.