问题描述
我想根据各自的字符串(基于字典)在我的 plotly xaxis 中以不同的颜色显示我的 ticktexts.plotly 中是否有功能可以做到这一点，也许是通过 HTML 编码?
ticktext = ['<font color="red">{}</font>'.format(x) for x in ticktexts]不起作用，它将 html 字符串提供给标签.
使用 LaTeX 的一点解决方法可以帮助你(对不起@Iwileczek，我偷了你的例子，希望你不要'不介意)因为 plotly 有完整的 LaTeX
2021 年 3 月更新:
如果您不想在输出中使用 MathJax 渲染的 LaTex 字体，请使用带有 HTML 样式的@Dapcer 的解决方案:
def color(color, text):return f"<span style='color:{str(color)}'>{str(text)} </span>>fig.update_layout(font=dict(family="Times New Roman") [...] 的示例:
I would like to display my ticktexts in my plotly xaxis with different colors based on the respective string (based on a dictionary). Is there a functionality in plotly to do this, maybe via HTML coding?
ticktext = ['<font color="red">{}</font> '.format(x) for x in ticktexts]
doesn't work, it gives the html string to the labels.
A little bit of a workaround using LaTeX can help you here (sorry @Iwileczek, I stole your example, hope you don't mind) because plotly has full LaTeX support:
def color(color, text):
s = '$color{' + str(color) + '}{' + str(text) + '}$'
return s
animals=['giraffes', 'orangutans', 'monkeys']
colors = ['red', 'green', 'yellow', 'blue']
ticks = [5, 10, 15, 20]
keys = dict(zip(ticks, colors))
fig = go.Figure([go.Bar(x=animals, y=[20, 14, 23])])
ticktext = [color(v, k) for k, v in keys.items()]
print(ticktext)
fig.update_layout(
yaxis=dict(tickmode='array', ticktext=ticktext, tickvals=ticks)
)
fig.show()
Update March 2021:
If you don't want to use the LaTex rendered font by MathJax in your output, use the solution of @Dapcer with an HTML styling:
def color(color, text):
return f"<span style='color:{str(color)}'> {str(text)} </span>"
Example with fig.update_layout(font=dict(family="Times New Roman") [...]:
这篇关于如何在情节中为ticktext着色?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！