本文介绍了range() 用于浮点数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
Is there a range() equivalent for floats in Python?
>>> range(0.5,5,1.5)
[0, 1, 2, 3, 4]
>>> range(0.5,5,0.5)
Traceback (most recent call last):
File "<pyshell#10>", line 1, in <module>
range(0.5,5,0.5)
ValueError: range() step argument must not be zero
解决方案
I don't know a built-in function, but writing one like [this](https://stackoverflow.com/a/477610/623735) shouldn't be too complicated.
def frange(x, y, jump):
while x < y:
yield x
x += jump
---
As the comments mention, this could produce unpredictable results like:
>>> list(frange(0, 100, 0.1))[-1]
99.9999999999986
To get the expected result, you can use one of the other answers in this question, or as @Tadhg mentioned, you can use decimal.Decimal as the jump argument. Make sure to initialize it with a string rather than a float.
>>> import decimal
>>> list(frange(0, 100, decimal.Decimal('0.1')))[-1]
Decimal('99.9')
Or even:
import decimal
def drange(x, y, jump):
while x < y:
yield float(x)
x += decimal.Decimal(jump)
And then:
>>> list(drange(0, 100, '0.1'))[-1]
99.9
[editor's not: if you only use positive jump and integer start and stop (x and y) , this works fine. For a more general solution see here.]
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