本文介绍了可以“list_display"在 Django ModelAdmin 中显示 ForeignKey 字段的属性?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有一个 Person 模型，它与 Book 有外键关系，它有许多字段，但我最关心的是 author(一个标准的 CharField).
I have a Person model that has a foreign key relationship to Book, which has a number of fields, but I'm most concerned about author (a standard CharField).
话虽如此，在我的 PersonAdmin 模型中，我想使用 list_display 显示 book.author:
With that being said, in my PersonAdmin model, I'd like to display book.author using list_display:
class PersonAdmin(admin.ModelAdmin):
list_display = ['book.author',]
我已经尝试了所有明显的方法，但似乎没有任何效果.
I've tried all of the obvious methods for doing so, but nothing seems to work.
有什么建议吗?
推荐答案
作为另一种选择，您可以进行如下查找:
As another option, you can do look ups like:
class UserAdmin(admin.ModelAdmin):
list_display = (..., 'get_author')
def get_author(self, obj):
return obj.book.author
get_author.short_description = 'Author'
get_author.admin_order_field = 'book__author'
从 Django 3.2 开始，您可以使用 display() 装饰器:
Since Django 3.2 you can use display() decorator:
class UserAdmin(admin.ModelAdmin):
list_display = (..., 'get_author')
@display(ordering='book__author', description='Author')
def get_author(self, obj):
return obj.book.author
这篇关于可以“list_display"在 Django ModelAdmin 中显示 ForeignKey 字段的属性?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除！