问题描述
我已经花了几天时间试图找到一个使用正则表达式的解决方案(在有人说出来之前:我知道我应该使用 PHP DOM 文档库或类似的东西,但让我们把它当作一个理论问题),查找答案并我终于想出了在这个问题接近尾声时要展示的内容.
以下只是我之前尝试过的很多事情的总结.
首先,我所说的相同类型的嵌套标签是指:
任何 div 之外的文本<div id="my_id">布拉布拉<div>布拉布拉布拉<div style="这里有一些样式">啦啦啦啦啦我被困在一个 div 中!
div 之外的更多文字<div>更多 div 在这里!<div id="justbeingannoying">radiohead 规则</div>
现在假设我想使用正则表达式删除所有 div 及其内容.所以预期的结果是:
任何 div 之外的文本div 之外的更多文字
第一个想法是匹配所有内容.以下正则表达式匹配具有属性(样式、id 等)的 div 标签:
/]*>.*/sig
当然,问题在于这将匹配第一个
"开头之间的所有内容,因此它会匹配morediv 外的文本"也是(在这里查看:https://regex101.com/r/iR8mY2/1 ),这不是我们 (I) 想要的.这可以使用 U 修饰符(非贪婪)
解决/]*>.*/sigU
但是我们会遇到比我们想要的少的问题:它只会匹配从第一个< div"到第一个"(因此,如果我们删除匹配项,除了一些不匹配的标签之外,还会有文本我被困在 div 中!",这是我们不想要的).
所以,我找到了一个解决方案,它就像嵌套括号、方括号等的魅力:
/[([^[]]*+|(?R))*]/si
基本上,它的作用是找到一个左方括号,然后匹配任何*既不是左方括号也不是右方括号的*或它的递归结构,找到一个右方括号.
我现在的工作是一个糟糕的解决方案:基本上,首先我用方括号替换所有开始标签(由于其他原因,它不能出现在我的代码中),然后是结束方括号的结束标签然后我使用以前的正则表达式.我知道这不是一个非常优雅的解决方案.
问题是我真的很想知道如何只用一个正则表达式就可以做到这一点.看起来比在前面的正则表达式中用 html 标签替换["和]"很明显必须起作用.但并没有那么容易.问题是字符的否定 ("[^.......]" 对像 "div" 这样的字符串不起作用.似乎可以通过以下方式实现类似的东西:
.+?(?=)当然,结束标记也是如此
.+?(?=
这或多或少是我到达这个正则表达式的方式
/)|.+?(?=
))|(?R))*;/地理信息系统
这与我之前介绍的第一个正则表达式完全一样:https://regex101.com/r/yU8pV3/1
那么,这是我的问题:那个正则表达式有什么问题?
谢谢!
解决方案 免责声明
由于这个问题得到了积极的回应,我将发布一个答案来解释您的方法有什么问题,并将展示如何匹配不是特定文本的文本.
但是,我想强调:不要用它来解析真实的、任意的 HTML 代码,因为正则表达式只能用于纯文本.
你的正则表达式有什么问题
您的正则表达式包含 <div((.+?(?=</div>)|.+?(?=<div>))|(?R))*
部分(与 <div((.+?(?=</?div>))|(?R))*
) 匹配结束之前的 </div>
部分.当您有一些分隔文本时,不要依赖简单的懒惰/贪婪点匹配(除非用于展开循环结构 - 当您知道自己在做什么时).它的作用是:
<div
- 从字面上匹配 (同样,在 中,由于缺少单词边界或 s
之后)(
- 第 1 组匹配:(.+?(?=</div>)|.+?(?=<div>))
- 匹配任意 1+ 个字符(尽可能少)直到第一个
或第一个 |
(?R)
- 递归(即插入和使用))*
- 重复第 1 组零次或多次.问题很明显:(.+?(?=</?div>))
部分不排除匹配的
或 </div>
,这个分支必须只匹配文本 NOT EQUAL 到前导和尾随定界符.解决方案
要匹配某些特定文本以外的文本,请使用 tempered greedy token.>
((?:(?!?div).)+|(?R))*;s*^^^^^^^^^^^^^^^^^^^
查看正则表达式演示.请注意,您必须使用 DOTALL 修饰符才能跨换行符匹配文本.捕获组是多余的,您可以将其删除.
这里重要的是 (?:(?!</?div).)+
只匹配 1 个或多个不是 <div....>
或 </div
序列.请参阅我上面链接的线程,了解其工作原理.
至于性能,缓和的贪婪令牌非常消耗资源.展开循环技术来拯救:
(?:[^<]+(?:<(?!/?div)[^<]*)*|(?R))*s*
参见这个正则表达式演示
现在,令牌看起来像 [^<]+(?:<(?!/?div)[^<]*)*
: 1+ characters other比 <
后面跟着 0+ 个 <
序列,后面没有 /div
或 div
(如一个完整的词),然后又是 0+ 个非<
s.
可能仍然匹配 ,所以也许 ) 是通过正则表达式处理此问题的更好方法.尽管如此,使用DOM解析HTML要容易得多.I've been days trying to find a solution WITH regex (before somebody says it: I know I should been using the PHP DOM Document library or something alike, but let's take this as a theoretical question), looking answers up and I finally came up with what I'll show near the end of this question.
What follows is just a summary of a lot of things I've tried before.
First of all, what I mean by nested tags of the same type is:
Text outside any div
<div id="my_id"> bla bla
<div>
bla bla bla
<div style="some style here">
lalalalala
</div>
</div>
I'm trapped in a div!
</div>
more text outside divs
<div>more divs here!
<div id="justbeingannoying">radiohead rules</div>
</div>
Now imagine I want to remove all the divs and their content using regex. So the intended result would be:
Text outside any div
more text outside divs
The first idea would be matching everything. The following regex matches div tags with properties (style, id, etc):
/<div[^>]*>.*</div>/sig
The problem, of course, is that this will match everything between the beginning of the first "< div" and the last "< /div >", so it will match "more text outside divs" too (check here: https://regex101.com/r/iR8mY2/1 ), which is not want we (I) want.
This could be solved using the U modifier (Ungreedy)
/<div[^>]*>.*</div>/sigU
but then we'll have the problem of having less than we want: it will match only from the first "< div" till the first "" (so, if we remove the matches, besides some unmatched tags, will have the text "I'm trapped in a div!", which we don't want).
So, I found a solution that works like a charm for nested parenthesis, square brackets, etc:
/[([^[]]*+|(?R))*]/si
Basically, what this does is finding an opening square bracket, then matching anything *that is neither an opening nor a closing square bracket * OR a recursive structure of that, finding a closing square bracket.
What I have working now is a bad solution: basically, first I replace all the opening tags with an square bracket (which can't be in my code, for other reasons), then the closing tag for a closing square bracket and then I use the previous regex. Not a very elegant solution, I know.
The thing is I really want to know how this could be done with just one regex. It seems obvious than replacing in the previous regex the "[" and the "]" by the html tags has to work.
But is not that easy. The problem is the negation for characters ("[^.......]" doesn't work for strings like "div". It seems that something similar can be achieved by this:
.+?(?=<div>)
and, of course, the same for the closing tag
.+?(?=</div>
This is how, more or less, I arrived to this regex
/<div((.+?(?=</div>)|.+?(?=<div>))|(?R))*</div>/gis
Which works exactly as the first regex I presented before: https://regex101.com/r/yU8pV3/1
So, here is my question: what is wrong with that regex?
Thank you!
解决方案 DISCLAIMER
Since the question is met with positive reaction, I will post an answer explaining what is wrong with your approach, and will show how to match text that is not some specific text.
HOWEVER, I want to emphasize: Do not use this to parse real, arbitrary HTML code, as regex should only be used on plain text.
What is wrong with your regex
Your regex contains <div((.+?(?=</div>)|.+?(?=<div>))|(?R))*
part (same as <div((.+?(?=</?div>))|(?R))*
) before matching the closing </div>
part. When you have some delimited text, do not rely on plain lazy/greedy dot matching (unless used in unroll the loop structure - when you know what you are doing). What it does is this:
<div
- match <div
literally (also, in <diverse
due to a missing word boundary or a s
after it)
(
- Group 1 that matches:
(.+?(?=</div>)|.+?(?=<div>))
- matches either any 1+ chars (as few as possible) up to the first </div>
or to the first <div>
|
(?R)
- Recurse (i.e. insert and use)
)*
- repeat Group 1 zero or more times.
The problem is clear: the (.+?(?=</?div>))
part does not exclude matching <div>
or </div>
, this branch MUST only match the text NOT EQUAL to the leading and trailing delimiters.
Solution(s)
To match text other than some specific text use a tempered greedy token.
<div[^<]*>((?:(?!</?div).)+|(?R))*</div>s*
^^^^^^^^^^^^^^^^^^^
See the regex demo. Note you must use a DOTALL modifier so as to be able to match text across newlines. A capturing group is redundant, you can remove it.
What is important here is that (?:(?!</?div).)+
only matches 1 or more characters that are not the starting character of a <div....>
or </div
sequences. See my above linked thread on how that works.
As for performance, tempered greedy tokens are resource-consuming. Unroll the loop technique comes to the rescue:
<div[^<]*>(?:[^<]+(?:<(?!/?div)[^<]*)*|(?R))*</div>s*
See this regex demo
Now, the token looks like [^<]+(?:<(?!/?div)[^<]*)*
: 1+ characters other than <
followed with 0+ sequences of <
that is not followed with /div
or div
(as a whole word) and then again 0+ non-<
s.
<div
might still match in <div-tmp
, so perhaps, <div(?:s|>)
is a better way to deal with this via regex. Still, parsing HTML with DOM is much easier.
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