问题描述
我正在尝试查找图像的 MIME 类型.PHP 有函数 getimagesize 但它只接受一个文件名，而我有一个图像资源" - 即从 imagecreatefromstring 创建的图像.
I'm trying to find the mime type of an image. PHP has the function getimagesize but that only takes a filename, whereas I have an image "resource" instead - i.e. an image created from imagecreatefromstring.
我找到了返回资源宽度/高度的函数 imagesx 和 imagesy 但我找不到任何函数可以告诉我资源中的 mime 类型.有人知道这样做的方法吗?
I found the functions imagesx and imagesy which return the width/height from a resource but I can't find any function that tell me the mime type from a resource. Anyone know of a way to do this?
注意:由于服务器设置奇怪，我们无法正常从服务器读取/写入文件，只能通过 FTP 层(我从中读取图像数据).
Note: Due to a weird server set up, we can't read/write files from the server normally, only through an FTP layer (which is where I read the image data from).
推荐答案
我知道这已经很老了，但以防万一有人像我一样看到这篇文章......
I know this is pretty old, but just in case someone come across this post like I did...
从 PHP 5.4.0 发布的一个更好的选择:getimagesizefromstring
A better option it's been released from PHP 5.4.0: getimagesizefromstring
这个新函数与 getimagesize 完全相同，但允许您从流中检索信息.
This new function is exactly the same of getimagesize but allows you to retreive the information from a stream.
这篇关于从 PHP/GD 中的资源获取图像 mimetype?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！