本文介绍了如何计算数组中连续的重复值?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我有一个这样的数组:
$arr = array(1, 1, 1, 2, 2, 3, 3, 1, 1, 2, 2, 3);
我找到了函数 array_count_values()，但它会将所有相同的值分组并计算出现次数，而不考虑连续序列中的中断.
I found the function array_count_values(), but it will group all of the same values and count the occurrences without respecting breaks in the consecutive sequences.
$result[1] = 5
$result[2] = 4
$result[3] = 3
如何对每组连续值进行分组并计算每个序列的长度?请注意，数字 1、2 和 3 有两组序列.
How can I group each set of consecutive values and count the length of each sequence? Notice there are two sets of sequences for the numbers 1, 2, and 3.
我期望生成的数据需要类似于:
The data that I expect to generate needs to resemble this:
[1] = 3;
[2] = 2;
[3] = 2;
[1] = 2;
[2] = 2;
[3] = 1;
推荐答案
只需手动即可:
$arr = array(1,1,1,2,2,3,3,1,1,2,2,3);
$result = array();
$prev_value = array('value' => null, 'amount' => null);
foreach ($arr as $val) {
if ($prev_value['value'] != $val) {
unset($prev_value);
$prev_value = array('value' => $val, 'amount' => 0);
$result[] =& $prev_value;
}
$prev_value['amount']++;
}
var_dump($result);
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