问题描述

我必须在我的 eloquent 中使用模型:

I have to user models in my eloquent:

• 用户
• 办公用户

OfficeUser 在 JWT 配置中定义为标准模型.现在我已经编写了一个中间件来验证它们中的每一个

OfficeUser is in defined in the JWT config as standard model. Now I have written a Middleware for authenticate each of them

授权用户:

public function handle($request, Closure $next)
{
    Config::set('auth.providers.users.model', AppUser::class);
    try {

        if (! $user = JWTAuth::parseToken()->authenticate()) {
            return response()->json(['user_not_found'], 404);
        }

    } catch (TymonJWTAuthExceptionsTokenExpiredException $e) {

        return response()->json(['token_expired'], $e->getStatusCode());

    } catch (TymonJWTAuthExceptionsTokenInvalidException $e) {

        return response()->json(['token_invalid'], $e->getStatusCode());

    } catch (TymonJWTAuthExceptionsJWTException $e) {

        return response()->json(['token_absent'], $e->getStatusCode());

    }

    return $next($request);
}

authOffice用户

authOfficeUser

public function handle($request, Closure $next)
{
    try {

        if (! $user = JWTAuth::parseToken()->authenticate()) {
            return response()->json(['user_not_found'], 404);
        }

    } catch (TymonJWTAuthExceptionsTokenExpiredException $e) {

        return response()->json(['token_expired'], $e->getStatusCode());

    } catch (TymonJWTAuthExceptionsTokenInvalidException $e) {

        return response()->json(['token_invalid'], $e->getStatusCode());

    } catch (TymonJWTAuthExceptionsJWTException $e) {

        return response()->json(['token_absent'], $e->getStatusCode());

    }

    return $next($request);
}

另外我为他们每个人都有一个登录功能:

Additionally I have a login function for each of them:

登录用户

if ($user){
        if (Hash::check($request->password, $user->password)) {
            // grab credentials from the request
            $credentials = $request->only('email', 'password');

            try {
                // attempt to verify the credentials and create a token for the user
                Config::set('auth.providers.users.model', AppUser::class);
                if (! $token = JWTAuth::attempt($credentials)) {
                    return response()->json(['error' => 'invalid_credentials'], 401);
                }
            } catch (JWTException $e) {
                // something went wrong whilst attempting to encode the token
                return response()->json(['error' => 'could_not_create_token'], 500);
            }

登录办公室用户

if ($user){
        if (Hash::check($request->password, $user->password)) {
            // grab credentials from the request
            $credentials = $request->only('email', 'password');

            try {
                // attempt to verify the credentials and create a token for the user
                Config::set('auth.providers.users.model', AppOfficeUser::class);
                if (! $token = JWTAuth::attempt($credentials)) {
                    return response()->json(['error' => 'invalid_credentials'], 401);
                }
            } catch (JWTException $e) {
                // something went wrong whilst attempting to encode the token
                return response()->json(['error' => 'could_not_create_token'], 500);
            }

不幸的是，当我登录并尝试调用 authUser 中间件后面的路由时，我得到一个user_not_found"

Unfortunately when I login and try to call a route behind the authUser Middleware I get an "user_not_found"

有人知道为什么会这样吗?OfficeUser 身份验证工作正常

Does anybody have an idea why this happens? OfficeUser authentication works fine

推荐答案

发帖给任何发现此问题的人

虽然不建议有两个用户表，但我有一个类似的要求，即与我们的一个客户设置 JWT.这就是我解决问题的方法.

Posting for anyone who finds this questions

Although it's not recommended to have two user tables, but I had a similar requirement of setting up JWT with one of our clients. This is how I solved the issue.

无需对 `config/auth.php' 中的提供者进行任何更改

'providers' => [
    'users' => [
        'driver' => 'eloquent',
           'model' => AppUser::class,
     ],

]

在您的身份验证控制器中，通过设置动态修改提供者使用的模型

In your authentication controller, dynamically modify the model used by the providers by setting

Config::set('auth.providers.users.model', AppTrainer::class);

示例代码

在 authenticate() 方法中

if ($credentials['user_type'] == 'consultant') {

Config::set('auth.providers.users.model', AppTrainer::class);

} else {
    Config::set('auth.providers.users.model', AppUser::class);
}

//Find the user

//Create the token
if ($user) {
   $customClaims = ['user_type' => $credentials['user_type']];
   $token = JWTAuth::fromUser($user,$customClaims);
} else {
  return response()->json(['error' => 'invalid_credentials'], 401);
}

在解析令牌以验证用户身份时，您也必须这样做.示例代码

You will have to do the same while parsing the token to authenticate the user as well. Example code

在 getAuthenticatedUser() 方法中

$payload = JWTAuth::parseToken()->getPayload();
$user_type = $payload->get('user_type');

if($user_type === 'consultant'){
   Config::set('auth.providers.users.model', AppTrainer::class);
}else{
   Config::set('auth.providers.users.model', AppUser::class);
}

if (!$user = JWTAuth::parseToken()->authenticate()) {
    return response()->json(['user_not_found'], 404);
}

这篇关于多用户模型 Laravel JWT Auth的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！