问题描述

我正在尝试通过他们的 PHP SDK 在我的亚马逊 S3 上上传图片.所以我做了一个小脚本来做到这一点.但是，我的脚本不起作用，我的异常也没有给我发回任何错误消息.

I'm trying to upload a picture on my amazon S3 via their PHP SDK. So I made a little script to do so. However, my script doesn't work and my exception doesn't send me back any error message.

我是 AWS 新手，感谢您的帮助.

I'm new with AWS thank you for your help.

代码如下:

配置.php

<?php 

return array(
'includes' => array('_aws'),
'services' => array(
  'default_settings' => array(
      'params' => array(
          'key'    => 'PUBLICKEY',
          'secret' => 'PRIVATEKEY',
          'region' => 'eu-west-1'
      )
    )
  )
);

?>

索引.php

 <?php


//Installing AWS SDK via phar
require 'aws.phar';

use AwsS3S3Client;
use AwsS3ExceptionS3Exception;

$bucket = 'infact';
$keyname = 'myImage';

// $filepath should be absolute path to a file on disk                      
$filepath = 'image.jpg';

// Instantiate the client.
$s3 = S3Client::factory('config.php');

// Upload a file.
try {

$result = $s3->putObject(array(
    'Bucket'       => $bucket,
    'Key'          => $keyname,
    'SourceFile'   => $filePath,
    'ContentType'  => 'text/plain',
    'ACL'          => 'public-read',
    'StorageClass' => 'REDUCED_REDUNDANCY'
));

 // Print the URL to the object.
    echo $result['ObjectURL'] . "
";
} catch (S3Exception $e) {
    echo $e->getMessage() . "
";
}

?>

我现在正在使用此代码，但它仍然无法正常工作.我什至没有错误或异常消息.

EDIT : I'm now using this code but its still not working. I don't even have error or exception message.

    <?php

require 'aws.phar';

use AwsS3S3Client;
use AwsS3ExceptionS3Exception;

$bucket = 'infactr';
$keyname = 'sample';
// $filepath should be absolute path to a file on disk                      
$filepath = 'image.jpg';

// Instantiate the client.
$s3 = S3Client::factory(array(
    'key'    => 'key',
    'secret' => 'privatekey',
    'region' => 'eu-west-1'

    ));

try {
    // Upload data.
    $result = $s3->putObject(array(
        'Bucket' => $bucket,
        'Key'    => $keyname,
        'SourceFile'   => $filePath,
        'ACL'    => 'public-read',
        'ContentType' => 'image/jpeg'
    ));

    // Print the URL to the object.
    echo $result['ObjectURL'] . "
";
} catch (S3Exception $e) {
    echo $e->getMessage() . "
";
}

?>

推荐答案

尝试这样的事情(来自 AWS 文档):

Try something like this (from the AWS docs):

<?php

require 'aws.phar';

use AwsS3S3Client;
use AwsS3ExceptionS3Exception;

$bucket = '<your bucket name>';
$keyname = 'sample';
// $filepath should be absolute path to a file on disk                      
$filepath = '/path/to/image.jpg';

// Instantiate the client.
$s3 = S3Client::factory(array(
    'key'    => 'your AWS access key',
    'secret' => 'your AWS secret access key'
));

try {
    // Upload data.
    $result = $s3->putObject(array(
        'Bucket' => $bucket,
        'Key'    => $keyname,
        'SourceFile'   => $filepath,
        'ACL'    => 'public-read'
    ));



    // Print the URL to the object.
    echo $result['ObjectURL'] . "
";
} catch (S3Exception $e) {
    echo $e->getMessage() . "
";
}

?>

只要您拥有正确的凭据，它就可以正常工作.请记住，密钥名称是您在 S3 中文件的名称，因此如果您想让您的密钥与您的文件具有相同的名称，您必须执行以下操作:$keyname = 'image.jpg'; .此外，jpg 通常不是 plain/text 文件类型，您可以省略该 Content-type 字段，或者您可以简单地指定:image/jpeg