问题描述
假设您有一个数组值 => 时间戳".这些值随着时间的推移而增加，但可以随时重置.
Suppose you have an array "value => timestamp". The values are increasing with the time but they can be reset at any moment.
例如:
$array = array(
1 => 6000,
2 => 7000,
3 => 8000,
7 => 9000,
8 => 10000,
9 => 11000,
55 => 1000,
56 => 2000,
57 => 3000,
59 => 4000,
60 => 5000,
);
我想从这个数组中检索所有缺失的值.
I would like to retrieve all the missing values from this array.
这个例子会返回:
array(4,5,6,58)
我不想要 9 到 55 之间的所有值，因为 9 比其他更高的值更新.
I don't want all the values between 9 and 55 because 9 is newer than the other higher values.
在实际情况下，脚本将处理数千个值，因此它需要高效.
In real condition the script will deal with thousands of values so it need to be efficient.
感谢您的帮助！
更新:如果算法更容易，初始数组可以按时间戳排序.
UPDATE : The initial array can be ordered by timestamps if it is easier for the algorithm.
更新 2:在我的示例中，这些值是 UNIX 时间戳，因此它们看起来更像这样:1285242603 但出于可读性原因，我对其进行了简化.
UPDATE 2 : In my example the values are UNIX timestamps so they would look more like this : 1285242603 but for readability reason I simplified it.
推荐答案
这是另一个解决方案:
$prev = null;
$missing = array();
foreach ($array as $curr => $value) {
if (!is_null($prev)) {
if ($curr > $prev+1 && $value > $array[$prev]) {
$missing = array_merge($missing, range($prev+1, $curr-1));
}
}
$prev = $curr;
}
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