本文介绍了如何使用 mysql_fetch_array 的结果?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
I'm using a while statement on this and I can echo each row fine i.e
echo $row['myrow'];
but what I want is to have the result put into a link like so:
echo "<img src='http://www.mysite.com/images/$row['myrow'].jpg'>";
But it doesn't work. What am I doing wrong?
解决方案
Either echo it this way:
echo "<img src='http://www.mysite.com/images/{$row['myrow']}.jpg'>";
Or, IMHO much better, this way:
echo "<img src='http://www.mysite.com/images/".$row['myrow'].".jpg'>";
Give the documentation on double quoted-strings a quick refresh.
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