本文介绍了将图像发送到 MySQL 的 Android 应用程序的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个 android 应用程序,它将图像发送到我的数据库;
I have an android application which sends an image to my database as;
public class NewProductActivity extends Activity {
// Progress Dialog
private ProgressDialog pDialog;
public String image_str;
JSONParser jsonParser = new JSONParser();
EditText inputName;
EditText inputPrice;
EditText inputDesc;
EditText inputImg;
Button btnTakePhoto;
ImageView imgTakenPhoto;
private static final int CAM_REQUREST = 1313;
// url to create new product
private static String url_create_product = "http://buiud.com/android_connect/create_product.php";
// JSON Node names
private static final String TAG_SUCCESS = "success";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.add_product);
// Edit Text
inputName = (EditText) findViewById(R.id.inputName);
inputPrice = (EditText) findViewById(R.id.inputPrice);
inputDesc = (EditText) findViewById(R.id.inputDesc);
//inputImg = (EditText) findViewById(R.id.imageView1);
Bitmap bitmap = BitmapFactory.decodeResource(getResources(),R.drawable.ic_launcher);
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.PNG, 90, stream); //compress to which format you want.
byte[] byte_arr = stream.toByteArray();
image_str = Base64.encodeToString(byte_arr, Base64.DEFAULT);
// Create button
Button btnCreateProduct = (Button) findViewById(R.id.btnCreateProduct);
// button click event
btnCreateProduct.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
// creating new product in background thread
new CreateNewProduct().execute();
}
});
btnTakePhoto = (Button) findViewById(R.id.button1);
imgTakenPhoto = (ImageView) findViewById(R.id.imageView1);
btnTakePhoto.setOnClickListener(new btnTakePhotoClicker());
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
// TODO Auto-generated method stub
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == CAM_REQUREST) {
Bitmap thumbnail = (Bitmap) data.getExtras().get("data");
imgTakenPhoto.setImageBitmap(thumbnail);
}
}
class btnTakePhotoClicker implements Button.OnClickListener
{
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
Intent cameraIntent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
startActivityForResult(cameraIntent, CAM_REQUREST);
}
}
/**
* Background Async Task to Create new product
* */
class CreateNewProduct extends AsyncTask<String, String, String> {
/**
* Before starting background thread Show Progress Dialog
* */
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(NewProductActivity.this);
pDialog.setMessage("Creating Product..");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
/**
* Creating product
* */
protected String doInBackground(String... args) {
String name = inputName.getText().toString();
String price = inputPrice.getText().toString();
String description = inputDesc.getText().toString();
//String image_str = inputImg.getText().toString();
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("name", name));
params.add(new BasicNameValuePair("price", price));
params.add(new BasicNameValuePair("description", description));
params.add(new BasicNameValuePair("img",image_str));
//params.add(new BasicNameValuePair("image", image));
// getting JSON Object
// Note that create product url accepts POST method
JSONObject json = jsonParser.makeHttpRequest(url_create_product,
"POST", params);
// check log cat fro response
Log.d("Create Response", json.toString());
// check for success tag
try {
int success = json.getInt(TAG_SUCCESS);
if (success == 1) {
// successfully created product
Intent i = new Intent(getApplicationContext(), AllProductsActivity.class);
startActivity(i);
// closing this screen
finish();
} else {
// failed to create product
}
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
/**
* After completing background task Dismiss the progress dialog
* **/
protected void onPostExecute(String file_url) {
// dismiss the dialog once done
pDialog.dismiss();
}
}
}
即使我希望图像为 .png,但它在数据库中显示为 .bin,我该如何更改它,我已经阅读了有关在应用程序调用 create.php 但没有雪茄时输入内容的信息.我什至无法在 HTML 页面上将 .bin 显示为图像.
Even thought I want the image to be .png it appears on the database as .bin, how can I change that, I have read about typing something when the application was calling the create.php but no cigar. I can't even display the .bin as an image on the HTML page.
推荐答案
<?php
$name = $_POST['image'];
$entry = base64_decode($name);
$image = imagecreatefromstring($entry);
$directory = dirname(__FILE__).DIRECTORY_SEPARATOR."images/".DIRECTORY_SEPARATOR."index".$title.".jpeg";
header ( 'Content-type:image/jpeg' );
$imagetojpg=imagejpeg($image, $directory);
imagedestroy($image );
readfile ($directory);
exit ();
?>
这应该可以正常工作.image 是一个包含 base64 编码字符串的变量.
This should work fine.image is a variable which contain base64 encoded string.
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