问题描述

我正在寻找一种方法来比较两个 NSMutableArray 对象的内容.两个数组都填充了 NSMutableDictionaries，它们分别分配但偶尔包含相同的数据.

I am looking for a way to compare the contents of two NSMutableArray objects. Both arrays are filled with NSMutableDictionaries which were allocated separately but occasionally contain the same data.

简化示例:

NSMutableArray *firstArray = [[NSMutableArray alloc] init];
NSMutableArray *secondArray = [[NSMutableArray alloc] init];

NSMutableDictionary *a = [[NSDictionary alloc] init];
[a setObject:@"foo" forKey:"name"];
[a setObject:[NSNumber numberWithInt:1] forKey:"number"];

NSMutableDictionary *b = [[NSDictionary alloc] init];
[b setObject:@"bar" forKey:"name"];
[b setObject:[NSNumber numberWithInt:2] forKey:"number"];

NSMutableDictionary *c = [[NSDictionary alloc] init];
[c setObject:@"foo" forKey:"name"];
[c setObject:[NSNumber numberWithInt:1] forKey:"number"];

[firstArray addObject:a];
[firstArray addObject:b];
[secondArray addObject:c];

a、b、c 是不同的对象，但 a 和 c 的内容是匹配的.

a, b and c are distinct object, but the contents of a and c match.

我正在寻找的是一个比较 firstArray 和 secondArray 并且只返回 b 的函数/方法.

What I am looking for is a function / approach to compare firstArray and secondArray and return only b.

在伪代码中:

NSArray *difference = [self magicFunctionWithArray:firstArray andArray:secondArray];
NSLog(@"%@",difference)

=> ({name="bar"; number=2})

提前谢谢你.

推荐答案

这可以使用 NSMutableSet 实例来实现.

This can be achieved using NSMutableSet instances.

NSMutableSet * firstSet = [NSMutableSet setWithArray:firstArray];
NSMutableSet * secondSet = [NSMutableSet setWithArray:firstArray];

[firstSet unionSet:[NSSet setWithArray:secondArray]];
[secondSet intersectSet:[NSSet setWithArray:secondArray]];

[firstSet minusSet:secondSet];

NSLog(@"%@", firstSet);

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