问题描述

基本上我需要一个图像按钮，特别是一个自定义对象:
1) 点击时调用控制器的动作
2) 封装自定义数据
3) 由包装视图自动移动(不相关)

basically I need an image button, specifically a custom object that:
1) calls a controller's action when tapped
2) encapsulates custom data
3) is automatically moved by wrapper view (not relevant)

好吧，我通过 UIControl 的子类得到了所有这些(因为不推荐子类化 UIButton 并且子类化 UIImageView 使得管理第 1 点).但是现在突出显示它的正确方法是什么?我想在以任何方式点击时突出显示控件(即使是简单的 alpha 瞬间减少).

Well, I got all this with a subclass of UIControl (since subclassing UIButton is not recommended and subclassing UIImageView makes difficult to manage the point 1). But now what is the correct way to highlight it? I would like to highlight the control when tapped in any way (even a simple momentary reduction of alpha).

使用 beginTrackingWithTouch 和 endTrackingWithTouch 我无法识别唯一的 UIControlEventTouchUpInside 事件.

With beginTrackingWithTouch and endTrackingWithTouch I can't recognize the only UIControlEventTouchUpInside event.

控制器中的视图动画?在我看来这是一个粗略的解决方案

A view animation in the controller? It seems to me a rough solution

有没有简单直接的解决方案?

Is there a simple and immediate solution?

谢谢:(

推荐答案

我认为 UIControls 会自动正确设置其突出显示的属性，仅基于触摸事件.您需要重写 -setHighlighted: 方法来实现特定算法:

I think UIControls automatically set their highlighted property correctly, based solely on touch events. What you need is to override -setHighlighted: method to implement a specific algorithm:

- (void) setHighlighted: (BOOL) highlighted {
    [super setHighlighted: highlighted];
    // Only as an example. Caution: looks like a disabled control
    self.alpha = highlighted ? 0.5f : 1.0f;
}

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