问题描述

如果我有一个 UIFont 对象，是否可以将其转换为粗体?我不知道字体名称，我只有一个 UIFont 对象.我想要的是这样的功能

If I have a UIFont object, is it possible to convert it to bold? I don't know the font name, I just have a UIFont object. What I want is a function like

UIFont *boldFontFromFont(UIFont *input)
{
    return [input derivedFontWithFontWeight:UIFontWeightBold];
}

如何更改代码以使其正常工作.(上面的代码不起作用，我只是为了说明这一点而编造的.)

How can I change the code so that it works. (The code above does not work, I just made it up to illustrate the point.)

提前致谢.

推荐答案

要获得粗体字体，您需要从字体系列中传递特定的字体名称.您可以从给定字体中获取字体系列名称，然后列出该系列中的所有字体.通常，粗体字体的名称中会包含粗体"，但格式并不严格，并且可能存在诸如Helvetica-BoldOblique"之类的变体.你可以从这段代码开始:

To get a bold font you need to pass a specific name of the font from a font family. You can get a font family name from a given font, then list all fonts from this family. In general, a bold font will contain "bold" in its name, but the format isn't strict and there could be variations like "Helvetica-BoldOblique", for example. You can start from this code:

- (UIFont *)boldFontFromFont:(UIFont *)font
{
    NSString *familyName = [font familyName];
    NSArray *fontNames = [UIFont fontNamesForFamilyName:familyName];
    for (NSString *fontName in fontNames)
    {
        if ([fontName rangeOfString:@"bold" options:NSCaseInsensitiveSearch].location != NSNotFound)
        {
            UIFont *boldFont = [UIFont fontWithName:fontName size:font.pointSize];
            return boldFont;
        }
    }
    return nil;
}

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