问题描述
我在我的 Spring Boot 应用程序中使用 JWT.当我尝试从 Angular 6 客户端登录时，出现 CORS 错误
I am using JWT in my Spring Boot app. When I try to login from the Angular 6 client, I get the CORS error
Access to XMLHttpRequest at 'http://localhost:8082/login' from origin 'http://localhost:4200' has been blocked by CORS policy: Response to preflight request doesn't pass access control check: It does not have HTTP ok status.
我尝试为 "Access-Control-Allow-Origin 添加标头，我什至尝试使用一些 chrome 扩展，但仍然无法绕过 CORS.我可以使用 Postman 访问登录 API 和获取令牌.
I tried adding headers for "Access-Control-Allow-Origin, I even tried using some chrome extensions and still it couldn't bypass the CORS. I can access the login API with Postman and get the token.
Spring Boot 类
Spring Boot Classes
WebSecurityConfig.java
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
private UserDetailsService userDetailsService;
private BCryptPasswordEncoder bCryptPasswordEncoder;
public WebSecurityConfig(@Qualifier("customUserDetailsService") UserDetailsService userDetailsService, BCryptPasswordEncoder bCryptPasswordEncoder) {
this.userDetailsService = userDetailsService;
this.bCryptPasswordEncoder = bCryptPasswordEncoder;
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.csrf().disable().authorizeRequests()
.antMatchers(HttpMethod.POST, SIGN_UP_URL).permitAll()
.anyRequest().authenticated()
.and()
.addFilter(new JWTAuthenticationFilter(authenticationManager()))
.addFilter(new JWTAuthorizationFilter(authenticationManager()));
}
@Override
public void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.userDetailsService(userDetailsService).passwordEncoder(bCryptPasswordEncoder);
}
WebConfig.java
@Configuration
public class WebConfig implements WebMvcConfigurer {
@Override
public void addCorsMappings(CorsRegistry corsRegistry) {
corsRegistry.addMapping( "/**" )
.allowedOrigins( "http://localhost:4200" )
.allowedMethods( "GET", "POST", "DELETE" )
.allowedHeaders( "*" )
.allowCredentials( true )
.exposedHeaders( "Authorization" )
.maxAge( 3600 );
}
}
JWTAuthorization.java 授予用户访问权限的类
JWTAuthorization.java the class that gives access to user
@Order(Ordered.HIGHEST_PRECEDENCE)
public class JWTAuthorizationFilter extends BasicAuthenticationFilter {
public JWTAuthorizationFilter(AuthenticationManager authenticationManager) {
super(authenticationManager);
}
@Override
protected void doFilterInternal(HttpServletRequest request, HttpServletResponse response, FilterChain chain) throws IOException, ServletException {
String header = request.getHeader(HEADER_STRING);
response.setHeader("Access-Control-Allow-Origin", "*");
response.setHeader("Access-Control-Allow-Methods", "POST, GET, OPTIONS, DELETE");
response.setHeader("Access-Control-Max-Age", "3600");
response.setHeader("Access-Control-Allow-Credentials", "true");
response.setHeader("Access-Control-Allow-Headers", "Origin,Accept,X-Requested-With,Content-Type,Access-Control-Request-Method,Access-Control-Request-Headers,Authorization");
if (header == null || !header.startsWith(TOKEN_PREFIX)) {
chain.doFilter(request, response);
return;
}
UsernamePasswordAuthenticationToken authenticationToken = getAuthenticationToken(request);
SecurityContextHolder.getContext().setAuthentication(authenticationToken);
chain.doFilter(request, response);
}
private UsernamePasswordAuthenticationToken getAuthenticationToken(HttpServletRequest request){
String token = request.getHeader(HEADER_STRING);
if (token != null) {
// parse the token.
String user = Jwts.parser()
.setSigningKey(SECRET)
.parseClaimsJws(token.replace(TOKEN_PREFIX, ""))
.getBody()
.getSubject();
System.out.println(user);
if (user != null) {
return new UsernamePasswordAuthenticationToken(user, null, new ArrayList<>());
}
return null;
}
return null;
}
}
JWTAuthenticationFilter.java 处理登录请求并返回令牌的类
JWTAuthenticationFilter.java the class that handles the login request and returns the token
public class JWTAuthenticationFilter extends UsernamePasswordAuthenticationFilter {
private AuthenticationManager authenticationManager;
public JWTAuthenticationFilter(AuthenticationManager authenticationManager) {
this.authenticationManager = authenticationManager;
}
@Override
public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response) throws AuthenticationException {
try {
User user = new ObjectMapper().readValue(request.getInputStream(),User.class);
return authenticationManager.authenticate(
new UsernamePasswordAuthenticationToken(
user.getUsername(),
user.getPassword())
);
} catch (IOException e) {
throw new RuntimeException(e);
}
}
@Override
protected void successfulAuthentication(HttpServletRequest request, HttpServletResponse response, FilterChain chain, Authentication authResult) throws IOException, ServletException {
String username = ((org.springframework.security.core.userdetails.User) authResult.getPrincipal()).getUsername();
String token = Jwts
.builder()
.setSubject(username)
.setExpiration(new Date(System.currentTimeMillis() + EXPIRATION_TIME))
.signWith(SignatureAlgorithm.HS512, SECRET)
.compact();
System.out.println("TOKEN: " + token);
String bearerToken = TOKEN_PREFIX + token;
response.getWriter().write(bearerToken);
response.addHeader(HEADER_STRING, bearerToken);
}
}
有效的邮递员示例
这是我发出登录请求的方式，但会出现错误
Here is how I make the post request to login that gives me the error
@Injectable({
providedIn: 'root'
})
export class AuthenticationService {
public apiURL:string="http://localhost:8082";
constructor(private httpClient:HttpClient) { }
validateUser(user:User){
let userData = "username=love"+ "&password=12345" + "&grant_type=password";
let reqHeader = new HttpHeaders({ 'Content-Type': 'application/json' });
const data = new FormData();
data.append("username", user.username);
data.append("password", user.password);
console.log(data);
return this.httpClient.post<User>(this.apiURL + '/login',data,{headers:reqHeader});
}
storeToken(token: string) {
localStorage.setItem("token", token);
}
getToken() {
return localStorage.getItem("token");
}
removeToken() {
return localStorage.removeItem("token");
}
}
还有 Angular 中的 User 界面
Also the User interface in Angular
export interface User {
username:string;
password:string;
}
推荐答案
由于消息是关于您的 preflight 请求，即 OPTIONS 请求，
Since message is about your preflight request i.e. OPTIONS request,
我猜，你需要在服务器端/Spring Boot 代码上做两件事，
I guess, you need to do two things on server side / Spring Boot code ,
- 从身份验证过滤器返回 OK，因此需要在
attemptAuthentication方法中添加以下内容作为第一个检查，即不对预检请求进行真正的身份验证，
- Return OK from Authentication filter so need to add below in
attemptAuthenticationmethod as first check i.e. don't do real authentication for preflight requests,
if (CorsUtils.isPreFlightRequest(httpServletRequest)) {httpServletResponse.setStatus(HttpServletResponse.SC_OK);返回新的身份验证()；//无论你的令牌实现类是什么 - 返回它的一个实例
}
CorsUtils 是 - org.springframework.web.cors.CorsUtils
CorsUtils is - org.springframework.web.cors.CorsUtils
- 让 Spring Security 将 Authorized Options 请求输入到系统中，因此在 Security Config 中添加这些行，
.authorizeRequests().antMatchers(HttpMethod.OPTIONS, "/**").permitAll()
您也可以允许未经授权的 OPTIONS 请求，但我想这不是一个好主意.此外，如果可能，请尝试将/**"缩小到特定的 URL.
You can allow unauthorized OPTIONS requests too but I guess , that wouldn't be a good idea. Also, try to narrow down "/**" to specific URLs if possible.
这篇关于带有 Angular 6 的 Spring Boot JWT CORS的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！