问题描述

我有一个具有相同键但不同值的 json 文件，如下所示，

I have a json file with same key but different values as follows,

{
    "domains" : {
        "A" : {
            "name" : "a",
            "type" : "a1"
        },
        "B"  :{
            "name" : "r",
            "type" : "g1"
         },
        "A" : {
           "name" : "b",
           "type" : "b1"
        }
    }
}

来自外部系统.如何将json转成java map对象并访问key的不同值:A

which is coming from external system. How to convert the json to java map object and access the different values of the key: A

我正在使用类似下面的东西，

I am using something like below,

map = mapper.readValue(json, new TypeReference<HashMap<String,String>>(){});

它返回一个带有唯一键的映射.但我需要一个地图对象来保存 json 文件中的所有数据.

which returns a map with unique keys. But I need a map object to hold all the data from json file.

无论如何要做到这一点?

Anyway to achieve this?

推荐答案

我同意@fge 的评论.

I agree with comments by @fge.

但如果你真的坚持要解决这个问题，你可以继承 HashMap(或任何其他 Map)，覆盖它的 put 方法，并使用您想要的任何机制处理重复项.只要确保你的 Map 有一个无参数的构造函数.

But if you really insists on solving this, you could sub-class HashMap (or any other Map), override its put method, and handle duplicates using whatever mechanism you want. Just make sure your Map has a no-arguments constructor.

Guava 也可能具有允许保留重复项的数据类型(Multimap?).如果是这样，您将需要使用 Jackson 的 Guava 模块:https://github.com/FasterXML/jackson-datatype-guava

Guava may also have a datatype that would allow retaining duplicates (Multimap?). If so, you will want to use Jackson's Guava module: https://github.com/FasterXML/jackson-datatype-guava

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