本文介绍了SQL 查询以查找最近的一组记录的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有共享 IdString
的记录历史记录(每次更新的多条记录都具有完全相同的日期时间).
I have a history of records (multiple records per update all with the exact same datetime) that share an IdString
.
我想要一个查询来确定这些记录中的哪些是最近更新组的一部分.
I want a query to determine which of these records are part of the most recent update group.
此查询将向我显示一个具有最新更新日期的记录,但是对于每个分区,我需要具有该最大日期的所有记录..>
This query will show me one of the records having the most recent update date, but for each partition, I need all the records with that max date.
;with cte as(
select ROW_NUMBER() over (partition by IdString order by UpdateDate desc) as [rn], *
from MyTable
)
select CASE WHEN (cte.rn = 1) THEN 0 ELSE 1 END [IsOld], *
from MyTable m
inner join cte on cte.RecordId= m.RecordId
有人可以帮我找出合适的查询吗?
Would someone please help me figure out an appropriate query?
示例
(IsOld is the desired calculated value)
IsOld RecordId IdString UpdateDate
1 1 ABC 2011-06-16
1 2 ABC 2012-05-30
1 3 ABC 2008-12-31
0 4 ABC 2012-06-08
1 5 ABC 2011-01-16
0 6 ABC 2012-06-08
1 7 ABC 2012-06-07
1 8 XYZ 2001-01-16
1 9 XYZ 2013-01-30
0 10 XYZ 2001-01-31
1 11 XYZ 2013-06-01
1 12 XYZ 2001-05-04
0 13 XYZ 2013-01-30
推荐答案
试试这个 -
;WITH cte AS(
SELECT RANK() OVER(PARTITION BY IdString ORDER BY UpdateDate DESC) AS [row_num], *
FROM MyTable
)
SELECT CASE WHEN m.[row_num] = 1 THEN 0 ELSE 1 END isOld, *
from cte m
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