本文介绍了SQL - 选择分组行的一个实例的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个对行进行分组的查询.产品 ID 相同但日期和数量不同的多行被分组,以便我可以计算数量、平均价格等的总和.
I have a query where rows are grouped. Multiple rows where the product ID are the same but where date and quantity differs, are grouped so I can calculate the sum of quantities, average prices, etc.
我现在需要添加上次销售的日期和相应的数量.日期加了MAX(date),怎么加对应的数量?
I now need to add the date when the last sale occurred and the corresponding quantity. I added the date with MAX(date), but how do I add the corresponding quantity?
我使用 MS SQL Server Management Studio.
I use MS SQL Server Management Studio.
示例查询:
SELECT id,
SUM(quantity) as 'Total q',
AVG(price) as 'Avg price',
MAX(price) as 'Max price',
MAX(date) as 'Last sale date'
FROM table
WHERE date > 2018
GROUP BY id
原始样本数据:
id quantity price date
1 20 2.30 2018-6-2
1 10 2.40 2018-6-4
1 5 2.55 2018-6-10
2 15 12.50 2018-5-20
2 100 7.50 2018-6-1
2 50 10.00 2018-6-12
预期结果:
id total q avg price max price last sale last q last p
1 35 2.42 2.55 2018-6-10 5 2.55
2 165 10.00 12.50 2018-6-12 50 10.00
推荐答案
你可以使用窗口函数
:
SELECT DISTINCT id,
SUM(quantity) OVER(PARTITION BY id) as "Total q",
AVG(price) OVER(PARTITION BY id) as "Avg price",
MAX(price) OVER(PARTITION BY id) as "Max price",
MAX(_date) OVER(PARTITION BY id) as "Last sale date",
FIRST_VALUE(quantity) OVER(PARTITION BY id ORDER BY _date DESC) AS last_q,
FIRST_VALUE(price) OVER(PARTITION BY id ORDER BY _date DESC) AS last_p
FROM tab
WHERE _date > '2018-01-01';
输出:
┌────┬─────────┬───────────┬───────────┬─────────────────────┬────────┬────────┐
│ id │ Total q │ Avg price │ Max price │ Last sale date │ last_q │ last_p │
├────┼─────────┼───────────┼───────────┼─────────────────────┼────────┼────────┤
│ 1 │ 35 │ 2.416666 │ 2.55 │ 10/06/2018 00:00:00 │ 5 │ 2.55 │
│ 2 │ 165 │ 10.000000 │ 12.50 │ 12/06/2018 00:00:00 │ 50 │ 10.00 │
└────┴─────────┴───────────┴───────────┴─────────────────────┴────────┴────────┘
DBFiddle 演示
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