问题描述
Stackoverflow 上的某个地方有一个问题,虽然我现在找不到了,但它提醒发布者 .value
不会返回 .exist
s 的值.
There is a question somewhere on Stackoverflow, although i cannot find it now, that reminded the poster that .value
does not return the value that .exist
s.
那是因为 .value
总是写成要求 [1]
项,其中 .exist
到处可见.
That is because .value
is always written as asking for the [1]
item, where .exist
looks everywhere.
假设一个包含两个客户的 xml 文档:
Given a hypothetical xml document containing two customers:
<Customer>
<Name>Ian Boyd</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
</Customer>
<Customer>
<Name>Kirsten</Name>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Firearms Certificate</IDOtherDescription>
</IDInfo>
</Customer>
我想为具有 IDType 的任何客户返回 Name
、IDType
和 IDOtherDescription
3
(其他):
i want to return the Name
, IDType
, and IDOtherDescription
for any customers who have an IDType of 3
(Other):
DECLARE @xml XML;
SET @xml =
'<Customer>
<Name>Ian Boyd</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
</Customer>
<Customer>
<Name>Kirsten</Name>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Firearms Certificate</IDOtherDescription>
</IDInfo>
</Customer>'
--Wrap it up in a table, cause it makes it look more like my real situation
;WITH BatchReports AS (
SELECT @xml AS BatchFileXml
)
SELECT
BatchFileXml.value('(//Name)[1]', 'varchar(50)') AS Name,
BatchFileXml.value('(//IDType)[1]', 'varchar(50)') AS IDType,
BatchFileXml.value('(//IDOtherDescription)[1]', 'varchar(50)') AS IDOtherDescription,
*
FROM BatchReports
--WHERE BatchFileXml.value('(//IDType)[1]', 'varchar(50)') = '3'
WHERE BatchFileXml.exist('//IDType[text()="3"]')=1
由于 .exist
is 满足,所以返回一行:
Since the .exist
is satisfied, it returns a row:
Name IDType IDOtherDescription
-------- ------ --------------------
Ian Boyd 1 Firearms Certificate
除非那不是我想要的.我想要 IDType = 3
的值.
Except that's not what i wanted. I wanted the values where IDType = 3
.
事情变得更加复杂,其中有多个 IDType
条目:
Things get even more complicated, where there are multiple IDType
entries:
<Customer>
<Name>Ian Boyd</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
</Customer>
<Customer>
<Name>Kirsten</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
<IDInfo>
<IDType>2</IDType>
</IDInfo>
<IDInfo>
<IDType>4</IDType>
</IDInfo>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Firearms Certificate</IDOtherDescription>
</IDInfo>
</Customer>
当您可以在其他级别找到 /IDInfo
节点时,情况会更加复杂:
And even more complicated when you can find /IDInfo
nodes in other levels:
<Customer>
<Name>Ian Boyd</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
<ThirdPartyInfo>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Sherrif Badge</IDOtherDescription>
</IDInfo>
</ThirdPartyInfo>
</Customer>
<Customer>
<Name>Kirsten</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
<IDInfo>
<IDType>2</IDType>
</IDInfo>
<IDInfo>
<IDType>4</IDType>
</IDInfo>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Firearms Certificate</IDOtherDescription>
</IDInfo>
</Customer>
最终结果是一样的.我需要一个查询来返回 exist
的 values
:
The end result is the same. I need a query to return the values
that exist
:
Name IDType IDOtherDescription
-------- ------ --------------------
Ian Boyd 3 Sherrif Badge
Kirsten 3 Firearms Certificate
奖金聊天
当我两年前设计系统并选择使用 XML
数据类型时,我认为在紧急情况下它会很有用.我可以使用一些 XPath 来过滤原始 xml.我忘记了 XPath 和 SQL Server 中的 XPath 是多么不可能.四个小时盯着文档和网站;我又饿又累.
Bonus Chatter
When i designed the system two years ago, and chose to use XML
data type, i figured it would be useful when there's an emergency. I can use some XPath to filter through the raw xml. I forgot how impossible XPath, and XPath in SQL Server is. Four hours of staring at documentation and web-sites; i'm hungry and tired.
推荐答案
以下是您可以尝试的查询:
Here is the query you can try:
;WITH BatchReports AS (
SELECT @xml AS BatchFileXml
)
SELECT a.BatchXml.value('(Name)[1]', 'varchar(50)') AS Name,
a.BatchXml.value('(IDInfo/IDType)[1]', 'varchar(50)') AS IDType,
a.BatchXml.value('(IDInfo/IDOtherDescription)[1]', 'varchar(50)') AS IDOtherDescription
FROM BatchReports b
CROSS APPLY b.BatchFileXml.nodes('Customer') A(BatchXml)
WHERE a.BatchXml.exist('IDInfo/IDType[text()=3]')=1
这里是从所有 XML 中检索必要信息的查询.
and here is the query which retrieve necessary information form all of the XMLs.
;WITH BatchReports AS (
SELECT @xml AS BatchFileXml
)
SELECT A.BatchXml.value('(Name)[1]', 'varchar(50)') AS Name,
B.BatchXml.value('(IDType)[1]', 'varchar(50)') AS IDType,
B.BatchXml.value('(IDOtherDescription)[1]', 'varchar(50)') AS IDOtherDescription
FROM BatchReports X
CROSS APPLY X.BatchFileXml.nodes('Customer') A(BatchXml)
CROSS APPLY A.BatchXml.nodes('//IDInfo') B(BatchXml)
WHERE A.BatchXml.exist('IDInfo/IDType[text()=3]')=1
AND B.BatchXml.exist('IDType[text()=3]')=1
这篇关于如何返回 SQL Server XPath 中存在的值?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!