本文介绍了Oracle XMLTable-从父节点获取列的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下 XML 结构:
I have the following XML structure:
<root>
<parent>
<parent_id>1</parent_id>
<parent_value>10000</parent_value>
<child>
<child_id>11</child_id>
<other_value>1000</other_value>
</child>
<child>
<child_id>12</child_id>
<other_value>1000</other_value>
</child>
</parent>
</root>
预期输出:
CHILD_ID PARENT_VALUE
---------- ------------
11 10000
12 10000
我尝试过的:
WITH xtbl AS (SELECT xmltype ('<root>
<parent>
<parent_id>1</parent_id>
<parent_value>10000</parent_value>
<child>
<child_id>11</child_id>
<other_value>1000</other_value>
</child>
<child>
<child_id>12</child_id>
<other_value>1000</other_value>
</child>
</parent>
</root>') AS xcol FROM dual)
SELECT myXmlTable.*
FROM xtbl
CROSS JOIN
xmltable ('/root/parent/child'
PASSING xcol
COLUMNS child_id NUMBER (5) PATH 'child_id',
parent_value NUMBER (10) PATH './parent_value') myXmlTable;
我的查询的问题是 parent_value
为空.请帮忙.
Problem with my query is that parent_value
comes to be null. Please help.
推荐答案
您正在寻找./parent_node
,它是一个
下 当前
节点.而那是不存在的.
You are looking for ./parent_node
, which is a <parent_node>
under the current <child>
node. And that doesn't exist.
你只需要提升一个层次:
You just need to go up a level:
parent_value NUMBER (10) PATH './../parent_value'
使用您的 CTE 进行演示并添加 ../
:
Demo with your CTE and just that added ../
:
WITH xtbl AS (SELECT xmltype ('<root>
<parent>
<parent_id>1</parent_id>
<parent_value>10000</parent_value>
<child>
<child_id>11</child_id>
<other_value>1000</other_value>
</child>
<child>
<child_id>12</child_id>
<other_value>1000</other_value>
</child>
</parent>
</root>') AS xcol FROM dual)
SELECT myXmlTable.*
FROM xtbl
CROSS JOIN
xmltable ('/root/parent/child'
PASSING xcol
COLUMNS child_id NUMBER (5) PATH 'child_id',
parent_value NUMBER (10) PATH './../parent_value') myXmlTable;
CHILD_ID PARENT_VALUE
---------- ------------
11 10000
12 10000
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