问题描述
表格定义
Table 1 (horizontal) 这是一个用户表
Table 1 (horizontal) This is a table of users
| id | name | phone |
---------------------
| 1 | Bob | 800 |
| 2 | Phil | 800 |
Table 2 (Vertical Table) 这是一个团队表
Table 2 (Vertical Table) This is a table of teams
| id | name |
------------------
| 1 | Donkey |
| 2 | Cat |
Table 3 (Vertical Table) 此表连接前两个
Table 3 (Vertical Table) This table is connecting the first two
| id | user_id | team_id |
--------------------------
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
<小时>
我的目标
我希望能够以返回以下信息的方式查询数据:
I would like to be able to query the data in such a way that i get the following back:
| id | name | phone | Donkey | Cat |
-------------------------------------
| 1 | Bob | 800 | 1 | 1 |
| 2 | Phil | 800 | 1 | Null |
此表将包含我的水平表数据,然后是其他两个垂直表的组合以创建附加列.表 2 最终成为列名标题.并且行值作为布尔值从表三中提取.
This table would have my horizontal table data, then a combination of the other two vertical tables to create the appended columns. Where table 2 ends up being the column name headings. And the row valus are pulled from table three as a boolean.
推荐答案
您正在寻找数据透视表:
You're chasing a pivot table:
select u.*,
sum(case when t1.name = 'Donkey' then 1 else 0 end) Donkey,
sum(case when t1.name = 'Cat' then 1 else 0 end) Cat
from users u
inner join user_team ut1
on u.id = ut1.user_id
inner join teams t1
on ut1.team_id = t1.id
group by name
演示:http://sqlfiddle.com/#!9/5fd33/7
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