本文介绍了SQL Server 用户定义函数来计算年龄段的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我创建了一个 UDF 来计算数据库中的年龄段.我使用了以下代码
I created a UDF to calculate age bracket in the database. i used the following codes
CREATE FUNCTION Agebracket(@Ages INT)
RETURNS VARCHAR
AS
BEGIN
DECLARE @Age_Group varchar
SET @Age_Group = CASE WHEN @Ages BETWEEN 0 AND 9 THEN '[0-9]'
WHEN @Ages BETWEEN 10 AND 19 THEN '[10-19]'
WHEN @Ages BETWEEN 20 AND 29 THEN '[20-29]'
WHEN @Ages BETWEEN 30 AND 39 THEN '[30-39]'
WHEN @Ages BETWEEN 40 AND 49 THEN '[40-49]'
WHEN @Ages BETWEEN 50 AND 59 THEN '[50-59]'
WHEN @Ages BETWEEN 60 AND 69 THEN '[60-69]'
WHEN @Ages BETWEEN 70 AND 79 THEN '[70-79]'
WHEN @Ages BETWEEN 80 AND 89 THEN '[80-89]'
WHEN @Ages BETWEEN 90 AND 99 THEN '[90-99]'
WHEN @Ages>=100 THEN '[100+]' end
RETURN @Age_Group
END
当我用下面的例子进行测试时:
when i test with the example below:
SELECT [dbo].[Agebracket](10)
输出为 [
.
关于我可以做什么的任何想法,因为我希望输出为 [10-19]
Any idea on what i can do as i expect the output to be [10-19]
推荐答案
用 DECLARE @Age_Group varchar(8)
替换 DECLARE @Age_Group varchar
并使你的函数成为返回 varchar(8)
.
Replace DECLARE @Age_Group varchar
with DECLARE @Age_Group varchar(8)
and also make your function to return varchar(8)
.
工作版本:
alter FUNCTION Agebracket(@Ages INT)
RETURNS VARCHAR(8)
AS
BEGIN
DECLARE @Age_Group varchar(8)
SET @Age_Group = CASE WHEN @Ages BETWEEN 0 AND 9 THEN '[0-9]'
WHEN @Ages BETWEEN 10 AND 19 THEN '[10-19]'
WHEN @Ages BETWEEN 20 AND 29 THEN '[20-29]'
WHEN @Ages BETWEEN 30 AND 39 THEN '[30-39]'
WHEN @Ages BETWEEN 40 AND 49 THEN '[40-49]'
WHEN @Ages BETWEEN 50 AND 59 THEN '[50-59]'
WHEN @Ages BETWEEN 60 AND 69 THEN '[60-69]'
WHEN @Ages BETWEEN 70 AND 79 THEN '[70-79]'
WHEN @Ages BETWEEN 80 AND 89 THEN '[80-89]'
WHEN @Ages BETWEEN 90 AND 99 THEN '[90-99]'
WHEN @Ages>=100 THEN '[100+]' end
RETURN @Age_Group
END
GO
SELECT [dbo].[Agebracket](10)
这是因为 SQL Server 假定 VARCHAR = VARCHAR(1),更糟糕的是,它会以静默方式截断值.
This is because SQL Server assumes VARCHAR = VARCHAR(1) and even worse, it will silently truncate the values.
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