本文介绍了SQL 将表数据修改为更紧凑的形式的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个表,其中包含如下建模的数据对:
I have a table with data pairs modeled like the following:
Id1 Id2
-----------
100 50
120 70
70 50
34 20
50 40
40 10
Id1
总是比 Id2
大.这些对代表要进行的替换.所以100会被50代替,然后50会被40代替,40会被10代替.
Id1
is always bigger then Id2
. The pairs represent replacements to be made. So 100 will be replaced with 50, but then 50 will be replaced with 40, which will then be replaced by 10.
所以结果是这样的:
Id1 Id2
-----------
100 10
120 10
34 20
有没有一种简洁的方式可以改变或加入这张表来表示这一点?
Is there a nice succinct way that I can alter, or join this table to represent this?
我知道我可以加入它本身类似于:
I know i can join it on itself something akin to:
SELECT t1.Id1, t2.Id2
FROM mytable t1
JOIN myTable t2 ON t2.Id1 = t1.Id2
但这需要多次通过,所以我为什么要问是否有更好的方法来完成它?
But this will require several passes, hence why i ask if there is a nicer way to accomplish it?
推荐答案
declare @t table(Id1 int, Id2 int)
insert @t values (100, 50)
insert @t values ( 120, 70)
insert @t values ( 70, 50)
insert @t values ( 34, 20)
insert @t values ( 50, 40)
insert @t values ( 40, 10)
;with a as
(
-- find all rows without parent <*>
select id2, id1 from @t t where not exists (select 1 from @t where t.id1 = id2)
union all -- recusive work down to lowest child while storing the parent id1
select t.id2 , a.id1
from a
join @t t on a.id2 = t.id1
)
-- show the lowest child for each row found in <*>
select id1, min(id2) id2 from a
group by id1
结果:
id1 id2
----------- -----------
34 20
100 10
120 10
这篇关于SQL 将表数据修改为更紧凑的形式的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本站部分内容来源互联网,如果有图片或者内容侵犯您的权益请联系我们删除!