本文介绍了如何在一个查询中连接一列中多行的字符串+内部连接的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个查询,结果如下:查询:
I have a query with the following result: query:
SELECT Tasks.TaskId, Comments.Comment, comments.timespent
FROM comments
INNER JOIN tasks ON comments.entityid = tasks.taskid
WHERE ( comments.entity = 1 )
GROUP BY Tasks.TaskId, Comments.Comment, comments.timespent
结果:
TaskID Comment TimeSpent
__________________________
111754 C1 4
111754 C2 1
111754 C3 79
请告诉我应该如何编写查询以获得如下结果:
Please tell me how should I write my query to get the result as follows:
TaskID Comment TimeSpent
__________________________________
111754 ,C1,C2,C3 84
提前致谢.
推荐答案
这是工作的 SQL Fiddle:http://sqlfiddle.com/#!3/3597a/3
Here's the working SQL Fiddle: http://sqlfiddle.com/#!3/3597a/3
这是实际工作的 SQL.
Here's the actual working SQL.
SELECT Tasks.TaskId, SUBSTRING(
(SELECT ',' + Comments.Comment
FROM Comments
INNER JOIN tasks ON comments.entityid = tasks.taskid
FOR XML PATH('')),2,200000) AS Comments
, SUM(comments.timespent) AS TimeSpent
FROM comments
INNER JOIN tasks ON comments.entityid = tasks.taskid
WHERE ( comments.entity = 1 )
GROUP BY Tasks.TaskId
创建表并填充数据
CREATE TABLE Tasks
(
TaskID NVARCHAR(20) NOT NULL,
);
CREATE TABLE Comments
(
Entity INT NOT NULL,
EntityID NVARCHAR(20) NOT NULL,
Comment NVARCHAR(50) NOT NULL,
TimeSpent INT NOT NULL
);
INSERT INTO Tasks VALUES
( '111754' );
INSERT INTO Comments VALUES
(1,'111754', 'C1',4 ),
(1,'111754', 'C2',1 ),
(1,'111754', 'C3',79 );
执行SQL
SELECT Tasks.TaskId, SUBSTRING(
(SELECT ',' + Comments.Comment
FROM Comments
INNER JOIN tasks ON comments.entityid = tasks.taskid
FOR XML PATH('')),2,200000) AS Comments
, SUM(comments.timespent) AS TimeSpent
FROM comments
INNER JOIN tasks ON comments.entityid = tasks.taskid
WHERE comments.entity = 1
GROUP BY Tasks.TaskId
查看结果.
TASKID COMMENTS TIMESPENT
111754 C1,C2,C3 84
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