问题描述

您好，我想知道 MySQL 中是否有一种方法可以在 MySQL 表中添加一行时自动向自己发送电子邮件?

Hi I was wondering if there was a way in MySQL to automatically send an e-mail to myself whenever there is a row added to a MySQL table?

推荐答案

实现这一点的最佳方法是使用触发器和 cron.创建一个通知队列"表，并在所需表中插入一行时使用触发器填充该表.

The best way to achieve this would be using a trigger and a cron. Create a 'notification queue' table and populate that with a trigger when a row is inserted in the desired table.

例如.

CREATE TABLE `notification_queue` (
  `notification_id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `sent` tinyint(1) unsigned NOT NULL,
  PRIMARY KEY (`notification_id`)
);

然后定义一个简单的触发器:

Then define a simple trigger:

DELIMITER $$
CREATE TRIGGER t_notification_insert 
AFTER INSERT ON [table_being_inserted]
FOR EACH ROW 
BEGIN 
    INSERT INTO `notification_queue` (`sent`) VALUES (0);
END$$
DELIMITER ;

从那时起，您需要做的就是在服务器上运行一个 crontab(比如每分钟)，它从 notification 表中选择 sent = 0，发送通知并设置 sent = 1

From that point, all you need to do is make a crontab run on the server (say every minute) which selects from the notification table where sent = 0, send the notification and set sent = 1

据我所知，这是在不读取 bin 日志的情况下从数据库中获取该信息的最佳方式.

As far as I know, that's the best way to get that information out of the DB without reading the bin logs.

如果您需要使用 cron 运行的脚本示例:

If you need an example of the script to run with cron:

#!/bin/bash

DB_USER=''
DB_PASS=''
DB_NAME=''

ID=`mysql -u$DB_USER -p$DB_PASS $DB_NAME -Bse "SELECT notification_id FROM notification_queue WHERE sent=0 LIMIT 1;"`

if [[ ! -z $ID ]] 
then
    # SEND MAIL HERE
    RESULT=`mysql -u$DB_USER -p$DB_PASS $DB_NAME -Bse "UPDATE notification_queue SET sent=1 WHERE notification_id = $ID;"`
    echo "Sent"
fi

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