本文介绍了使用 Sequelize 计算关联条目的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有两个表,locations 和
p>sensors
.sensors
中的每个条目都有一个指向 locations
的外键.使用 Sequelize,我如何从 locations
中获取所有条目以及 sensors
中与 locations
中的每个条目相关联的条目总数?
原始 SQL:
选择`位置`.*,COUNT(`sensors`.`id`) AS`sensorCount`从`位置`加入`sensors` ON`sensors`.`location`=`locations`.`id`;GROUP BY `locations`.`id`;
型号:
module.exports = function(sequelize, DataTypes) {var Location = sequelize.define("位置", {ID: {类型:DataTypes.INTEGER.UNSIGNED,主键:真},名称:DataTypes.STRING(255)}, {类方法:{关联:功能(模型){Location.hasMany(models.Sensor, {外键:位置"});}}});返回位置;};module.exports = function(sequelize, DataTypes) {var Sensor = sequelize.define("Sensor", {ID: {类型:DataTypes.INTEGER.UNSIGNED,主键:真},名称:DataTypes.STRING(255),类型: {类型:DataTypes.INTEGER.UNSIGNED,参考: {型号:传感器类型",关键:身份证"}},地点: {类型:DataTypes.INTEGER.UNSIGNED,参考: {模型:位置",关键:身份证"}}}, {类方法:{关联:功能(模型){Sensor.belongsTo(models.Location, {外键:位置"});Sensor.belongsTo(models.SensorType, {外键:类型"});}}});返回传感器;};
解决方案
使用 findAll()
与 include()
和 sequelize.fn()
COUNT
的代码>:
Location.findAll({属性: {包括:[[Sequelize.fn("COUNT", Sequelize.col("sensors.id")), "sensorCount"]]},包括: [{型号:传感器,属性:[]}]});
或者,您可能还需要添加 group
:
Location.findAll({属性: {包括:[[Sequelize.fn("COUNT", Sequelize.col("sensors.id")), "sensorCount"]]},包括: [{型号:传感器,属性:[]}],组:['Location.id']})
I have two tables, locations
and sensors
. Each entry in sensors
has a foreign key pointing to locations
. Using Sequelize, how do I get all entries from locations
and total count of entries in sensors
that are associated with each entry in locations
?
Raw SQL:
SELECT
`locations`.*,
COUNT(`sensors`.`id`) AS `sensorCount`
FROM `locations`
JOIN `sensors` ON `sensors`.`location`=`locations`.`id`;
GROUP BY `locations`.`id`;
Models:
module.exports = function(sequelize, DataTypes) {
var Location = sequelize.define("Location", {
id: {
type: DataTypes.INTEGER.UNSIGNED,
primaryKey: true
},
name: DataTypes.STRING(255)
}, {
classMethods: {
associate: function(models) {
Location.hasMany(models.Sensor, {
foreignKey: "location"
});
}
}
});
return Location;
};
module.exports = function(sequelize, DataTypes) {
var Sensor = sequelize.define("Sensor", {
id: {
type: DataTypes.INTEGER.UNSIGNED,
primaryKey: true
},
name: DataTypes.STRING(255),
type: {
type: DataTypes.INTEGER.UNSIGNED,
references: {
model: "sensor_types",
key: "id"
}
},
location: {
type: DataTypes.INTEGER.UNSIGNED,
references: {
model: "locations",
key: "id"
}
}
}, {
classMethods: {
associate: function(models) {
Sensor.belongsTo(models.Location, {
foreignKey: "location"
});
Sensor.belongsTo(models.SensorType, {
foreignKey: "type"
});
}
}
});
return Sensor;
};
解决方案
Use findAll()
with include()
and sequelize.fn()
for the COUNT
:
Location.findAll({
attributes: {
include: [[Sequelize.fn("COUNT", Sequelize.col("sensors.id")), "sensorCount"]]
},
include: [{
model: Sensor, attributes: []
}]
});
Or, you may need to add a group
as well:
Location.findAll({
attributes: {
include: [[Sequelize.fn("COUNT", Sequelize.col("sensors.id")), "sensorCount"]]
},
include: [{
model: Sensor, attributes: []
}],
group: ['Location.id']
})
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