本文介绍了oracle获取外键的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我想获取架构中的所有外键，就像这样.假设我有桌子
I'd like to get all foreign keys in a schema, like this. Let's say I have tables
users(id, username, pass, address_id)
和
地址(id，文本)
我在 users-address_id 上为地址中的 id 列定义了一个 FK.我应该如何编写一个返回 FK 列的查询，例如:用户，address_id，地址，id?
I have defined a FK on users-address_id to the id column in addresses. How should I write a query that would return me the FK columns like : users, address_id, addresses, id ?
谢谢！
SELECT *
FROM all_cons_columns a
JOIN all_constraints c ON a.owner = c.owner
AND a.constraint_name = c.constraint_name
JOIN all_constraints c_pk ON c.r_owner = c_pk.owner
AND c.r_constraint_name = c_pk.constraint_name
WHERE C.R_OWNER = 'TRWBI'
推荐答案
找到了！
这就是我要找的东西，谢谢大家的帮助.
this is what i was looking for, thanks everybody for helping.
SELECT a.table_name, a.column_name, uc.table_name, uc.column_name
FROM all_cons_columns a
JOIN all_constraints c ON a.owner = c.owner
AND a.constraint_name = c.constraint_name
JOIN all_constraints c_pk ON c.r_owner = c_pk.owner
AND c.r_constraint_name = c_pk.constraint_name
join USER_CONS_COLUMNS uc on uc.constraint_name = c.r_constraint_name
WHERE C.R_OWNER = 'myschema'
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