问题描述

我正在处理一个稍微复杂的(至少对我而言)mySQL 查询，其中包含一个子查询，但说实话并不好.

I am working on a slight complex (at least for me) mySQL query containing a subquery and it isn't going to well to be honest.

SELECT `products`.`id`, `product`.`price`, 
  ( SELECT `value` FROM (`productValues`) 
    WHERE `productValues`.`product` = 'product.id'
  ) as values 
FROM (`products`) WHERE`product`.`active` = 1

目前的结果是这样的:

Array
(
    [0] => Array
        (
            [id] => 1
            [active] => 1
            [price] => 1000
            [values] => 
        )
)

我想要的是 values 元素也成为一个数组，其中包含 Values 表中匹配的所有元素(WHERE productValues.product = product.id).

What I want is the values element to also become an array with all elements in the Values table which matches (WHERE productValues.product = product.id).

我做错了什么?

推荐答案

SELECT p.id, p.price, pv.`value`
FROM products p
  JOIN  productValues pv
  ON p.product_id=pv.product
WHERE p.active = 1
ORDER BY p.id;

为每个 pv.value 提供一个包含一行的表(顺便说一句，不建议使用保留字如 'value').按 p.id 对输出进行排序可确保特定产品的所有行都在一起.因此，在应用程序层中，循环遍历您的行，每次 p.id 更改时更改产品.

gives a table with one row for each pv.value (BTW, using reserved words like 'value' is not recommended). Ordering the output by p.id ensures that all the rows for a particular product are together. So, in the application layer, loop through your rows, changing product each time the p.id changes.

$old_id=NULL;
$datastructure=array();
while($arr=$result->fetch_assoc()){
  if($arr['id']!=$old_id){
    $datastructure[$arr['id']][price]=$arr['price'];
    $old_id=$arr['id'];
  }
  $datastructure[$arr['id']]['values'][]=$arr['value'];
}

我给出的结构可能比您要求的结构更灵活，因为它允许您通过数组键访问特定产品.

The structure I've given is perhaps more flexible than the one you asked for in that it allows you to access a particular product through the array key.

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