问题描述
我有一个包含一组范围(RangeA 和 RangeB)的 Oracle 表.这些列是 varchar,因为它们可以同时包含数字和字母数字值,如下例所示:
I've got an Oracle table that holds a set of ranges (RangeA and RangeB). These columns are varchar as they can hold both numeric and alphanumeric values, like the following example:
ID|RangeA|RangeB
1 | 10 | 20
2 | 21 | 30
3 | AB50 | AB70
4 | AB80 | AB90
我需要执行一个只返回具有数值的记录的查询,并对该查询执行计数.到目前为止,我已经尝试使用两个不同的查询来执行此操作,但没有任何运气:
I need to to do a query that returns only the records that have numeric values, and perform a Count on that query. So far I've tried doing this with two different queries without any luck:
查询1:
SELECT COUNT(*) FROM (
SELECT RangeA, RangeB FROM table R
WHERE upper(R.RangeA) = lower(R.RangeA)
) A
WHERE TO_NUMBER(A.RangeA) <= 10
查询 2:
WITH A(RangeA,RangeB) AS(
SELECT RangeA, RangeB FROM table
WHERE upper(RangeA) = lower(RangeA)
)
SELECT COUNT(*) FROM A WHERE TO_NUMBER(A.RangeA) <= 10
子查询工作正常,因为我得到的两条记录只有数值,但查询的 COUNT 部分失败.我应该只得到 1,但我得到了以下错误:
The subquery is working fine as I'm getting the two records that have only numeric values, but the COUNT part of the query is failing. I should be getting only 1 on the count, but instead I'm getting the following error:
ORA-01722: invalid number
01722. 00000 - "invalid number"
我做错了什么?非常感谢任何帮助.
What am I doing wrong? Any help is much appreciated.
推荐答案
可以用正则表达式测试每一列,判断是否为有效数字:
You can test each column with a regular expression to determine if it is a valid number:
SELECT COUNT(1)
FROM table_of_ranges
WHERE CASE WHEN REGEXP_LIKE( RangeA, '^-?d+(.d*)?$' )
THEN TO_NUMBER( RangeA )
ELSE NULL END
< 10
AND REGEXP_LIKE( RangeB, '^-?d+(.d*)?$' );
另一种选择是使用用户定义的函数:
Another alternative is to use a user-defined function:
CREATE OR REPLACE FUNCTION test_Number (
str VARCHAR2
) RETURN NUMBER DETERMINISTIC
AS
invalid_number EXCEPTION;
PRAGMA EXCEPTION_INIT(invalid_number, -6502);
BEGIN
RETURN TO_NUMBER( str );
EXCEPTION
WHEN invalid_number THEN
RETURN NULL;
END test_Number;
/
那么你可以这样做:
SELECT COUNT(*)
FROM table_of_ranges
WHERE test_number( RangeA ) <= 10
AND test_number( RangeB ) IS NOT NULL;
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