问题描述
我有一个获取搜索结果的查询,效果很好.
I have a query for getting search results, which works fine.
SELECT
individuals.individual_id,
individuals.unique_id,
TIMESTAMPDIFF(YEAR,individuals.day_of_birth,CURDATE()) AS age,
individuals_dynamics.id,
individuals_achievements.degree
FROM
individuals as individuals
LEFT JOIN
individuals_dynamics AS individuals_dynamics ON individuals.unique_id = individuals_dynamics.individual_id
LEFT JOIN
individuals_achievements AS individuals_achievements ON individuals.unique_id = individuals_achievements.individual_id
WHERE
$uuid_access_status $display_type $detailed_search_query
ORDER BY
$search_sort $search_order
从现在开始,我在每个人的 individuals_achievements
中有多个记录,这是我想要获取 MAX 值(最新 id)的地方.
From now on, I have more than one record in individuals_achievements
per each individual and this is the where I would like to get the MAX value (latest id).
我尝试了许多不同的查询,但总是收到错误在非对象上调用成员函数 rowCount().
I tried the many different queries but always was getting an error Call to a member function rowCount() on a non-object.
我理解这个错误的含义,但我不知道我在哪里犯了这个错误以及一般是什么问题.
I understand what that error means but I can't figure out where I'm making that mistake and what is wrong in general.
SELECT
individuals.individual_id,
individuals.unique_id,
TIMESTAMPDIFF(YEAR,individuals.day_of_birth,CURDATE()) AS age,
individuals_dynamics.id,
individuals_achievements.degree
FROM
individuals as individuals
LEFT JOIN
individuals_dynamics AS individuals_dynamics ON individuals.unique_id = individuals_dynamics.individual_id
INNER JOIN
(
SELECT
degree, MAX(id) AS latest_record
FROM
individuals_achievements
GROUP BY
latest_record
) individuals_achievements AS individuals_achievements ON individuals.unique_id = individuals_achievements.individual_id
WHERE
$uuid_access_status $display_type $detailed_search_query
ORDER BY
$search_sort $search_order
我在这里缺少什么?有什么帮助吗?
What am I missing here? Any help please?
推荐答案
这是你的 from
子句:
FROM
individuals as individuals
LEFT JOIN
individuals_dynamics AS individuals_dynamics ON individuals.unique_id = individuals_dynamics.individual_id
INNER JOIN
(
SELECT
degree, MAX(id) AS latest_record
FROM
individuals_achievements
GROUP BY
latest_record
) individuals_achievements AS individuals_achievements ON individuals.unique_id = individuals_achievements.individual_id;
我至少可以发现三个问题.第一个是individuals_achievements AS individual_achievements
;第二个是对不在子查询中的 individuals_achievements.individual_id
的引用.第三个是group by latest_record
.
I can spot at least three problems. The first is individuals_achievements AS individuals_achievements
; the second is the reference to individuals_achievements.individual_id
which isn't in the subquery. The third is the group by latest_record
.
FROM individuals LEFT JOIN
individuals_dynamics
ON individuals.unique_id = individuals_dynamics.individual_id LEFT JOIN
individuals_achievements
ON individuals.unique_id = individuals_achievements.individual_id JOIN
(SELECT ia.individual_id, MAX(ia.id) AS latest_record
FROM individuals_achievements ia
GROUP BY ia.individual_id
) iamax
ON individuals.unique_id = iamax.individual_id and
individuals_achievements.id = iamax.latest_record
这会添加一个额外的子查询,带有最新记录的 id.
This adds an additional subquery, with the id of the latest record.
顺便说一句,表别名与表名同名是多余的.这只会使查询变得混乱.此外,为别名使用表缩写是个好主意,例如 ia
表示 individuals_achievements
.因为这个答案只关注 from
子句,所以我没有做那个改变.
By the way, it is redundant to have a table alias be the same name as the table name. That just clutters up the query. Also, it is a good idea to use table abbreviations for the aliases, such as ia
for individuals_achievements
. Because this answer focuses only on the from
clause, I have not made that change.
这篇关于使用子查询选择 MAX 值以及 LEFT JOIN的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!