问题描述
要获得所选用户的待处理请求，我使用:
To get pending request for selected user I use:
SELECT f1.asker_user_id AS friend_id
FROM friends AS f1
LEFT JOIN friends AS f2
ON f1.asked_user_id = f2.asker_user_id
AND f1.asker_user_id = f2.asked_user_id
WHERE f1.status = 1 AND f2.status IS NULL
AND f1.asked_user_id = 2
http://www.sqlfiddle.com/#!2/0f7a0d5/65 正确返回用户 3.VALUES (3,2,1)
http://www.sqlfiddle.com/#!2/0f7a0d5/65 It correctly returns user 3. VALUES (3,2,1)
但我想获取有关此用户 3 的更多数据.
But I'd like to get more data about this user 3.
我需要 users 表中的 name_surname 和 avatar.并且该用户的所有 word_id 来自 connections 表，作为回报，该表将显示 words_en 中基于 words_en 的 wordcode>word_id.
I need name_surname and avatar from users table.
And all word_ids of this user from connections table, which in return would show word from words_en based on word_id.
感谢分配！
附言我试过这个:
SELECT a.name_surname,GROUP_CONCAT(Distinct w.word Order by w.word asc) AS words
FROM (
SELECT f1.asked_user_id AS friend_id,
f1.created,
u.name_surname,
u.avatar
FROM friends AS f1
LEFT JOIN friends AS f2 ON f1.asked_user_id = f2.asker_user_id
INNER JOIN users AS u ON f1.asked_user_id = u.id
AND f1.asker_user_id = f2.asked_user_id
WHERE f1.status = 1 AND f2.status IS NULL
AND f1.asker_user_id = 2
) a
LEFT JOIN connections c ON c.user_id = a.friend_id
LEFT JOIN words_en w ON c.word_id = w.id
GROUP BY 1;
推荐答案
基于这个问题和你之前的问题，我想你可能正在寻找这样的东西:
Based on this question and your previous questions, i think you might be looking for something like this:
SELECT u.name_surname,
u.avatar,
GROUP_CONCAT(DISTINCT w.word Order by w.word asc) AS words
FROM users u
INNER JOIN
(
SELECT f1.asker_user_id AS friend_id
FROM friends AS f1
LEFT JOIN friends AS f2
ON f1.asked_user_id = f2.asker_user_id
AND f1.asker_user_id = f2.asked_user_id
WHERE f1.status = 1 AND f2.status IS NULL
AND f1.asked_user_id = 2
) a ON a.friend_id = u.id
LEFT JOIN connections c ON u.id = c.user_id
LEFT JOIN words_en w ON w.id = c.word_id
GROUP BY u.id;
sqlfiddle 演示
这篇关于对朋友表的待处理朋友请求查询并从其他表中获取数据的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！