问题描述

尝试通过 MySQL 中的存储过程进行选择时出现以下错误.

Am getting the below error when trying to do a select through a stored procedure in MySQL.

用于操作="的排序规则 (latin1_general_cs,IMPLICIT) 和 (latin1_general_ci,IMPLICIT) 的非法混合

Illegal mix of collations (latin1_general_cs,IMPLICIT) and (latin1_general_ci,IMPLICIT) for operation '='

知道这里可能出了什么问题吗?

Any idea on what might be going wrong here?

表格的排序规则是latin1_general_ci，where子句中列的排序规则是latin1_general_cs.

The collation of the table is latin1_general_ci and that of the column in the where clause is latin1_general_cs.

推荐答案

这通常是由于比较两个不兼容的排序规则的字符串或试图将不同排序规则的数据选择到一个组合列中引起的.

This is generally caused by comparing two strings of incompatible collation or by attempting to select data of different collation into a combined column.

COLLATE 子句允许您指定查询中使用的排序规则.

The clause COLLATE allows you to specify the collation used in the query.

例如，下面的 WHERE 子句总是会给出您发布的错误:

For example, the following WHERE clause will always give the error you posted:

WHERE 'A' COLLATE latin1_general_ci = 'A' COLLATE latin1_general_cs

您的解决方案是为查询中的两列指定一个共享排序规则.这是一个使用 COLLATE 子句的示例:

Your solution is to specify a shared collation for the two columns within the query. Here is an example that uses the COLLATE clause:

SELECT * FROM table ORDER BY key COLLATE latin1_general_ci;

另一种选择是使用 BINARY 运算符:

Another option is to use the BINARY operator:

BINARY str 是 CAST(str AS BINARY) 的简写.

BINARY str is the shorthand for CAST(str AS BINARY).

您的解决方案可能如下所示:

Your solution might look something like this:

SELECT * FROM table WHERE BINARY a = BINARY b;

或者，

SELECT * FROM table ORDER BY BINARY a;

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