本文介绍了MySQL:使用来自查询的信息创建一个新表的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
在 MySQL 中，我想创建一个包含此查询中所有信息的新表:
In MySQL, I would like to create a new table with all the information in this query:
select * into consultaa2 from SELECT
CONCAT( 'UPDATE customers SET
customers_default_address_id= ',
(SELECT a.address_book_id FROM
address_book a where
c.customers_id=a.customers_id order by
address_book_id desc limit 1), '
WHERE customers_id = ', customers_id,
';') AS sql_statement FROM customers c
where c.customers_id > 3894;
查询太长，浏览器无法显示连接，我需要它来进行更新.
The query is too long for the browser to show the concat and I need this to make this updates.
推荐答案
*请注意，此方法不会创建表(根据 OP 标题).为此，请参阅 此答案.*
使用来自查询的信息插入表的格式为
Inserting into a table with information from a query is of the format
INSERT INTO <TABLE-1>
SELECT * FROM <TABLE-2>
在你的情况下，它会是
insert into consultaa2
SELECT CONCAT( 'UPDATE customers SET customers_default_address_id= ',
(SELECT a.address_book_id FROM address_book a where c.customers_id=a.customers_id order by address_book_id desc limit 1), ' WHERE customers_id = ', customers_id, ';') AS sql_statement FROM customers c where c.customers_id > 3894;
只需确保要插入的表中的列与选择查询返回的列匹配即可.
Just make sure the columns in the table you are inserting into and the columns returned from the select query match.
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