本文介绍了MySQL中具有相似ID的行的列乘法总和的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在名为purchases"的表中有 3 列:
I have 3 columns in a table called "purchases":
id amount price
2 2 21
2 5 9
3 8 5
我想对所有具有相似 ID 的行进行分组,并得到这个数组:
I want to group all rows with similar IDs and have this array as a result:
array([0] => [id => 2, total => 87 (because 2*21+5*9=87)], [1] => [id => 3, total => 40 (because 8*5=40)])
作为具有相似 ID 的行的 SUM(amount*price) 的总帐户.
我试过了
SELECT id, SUM(p.price*p.amount) total FROM purchases p GROUP by p.id
但效果不佳(即它没有达到我想要的,这是我上面写的).关于如何在 mysql 中执行此操作的任何想法?
but it doesn't work well (i.e. it doesn't achieve what I want, which is what I wrote above). Any ideas on how to do this in mysql?
查询返回的示例:
id amount price
2 3 89
2 3 19
SELECT id, SUM(p.price*p.amount) total FROM purchases p GROUP by p.id
==> [id => 2, total => 183]
推荐答案
SELECT
id,
SUM(amount*price) AS total
FROM mytable
GROUP BY id
数据:
| id | amount | price |
|----|--------|-------|
| 2 | 3 | 19 |
| 2 | 3 | 89 |
| 3 | 203 | 1 |
结果:
id total
2 324
3 203
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