问题描述
所以我有一个如下所示的插入:
So I have an insert which looks like this:
INSERT INTO TempDupeData (Sys_InvoiceID, DupeSetID, Netted, InvoiceNo, InvoiceDate, Sys_SupplierID, SuppInvNo, NetAmount, VATAmount, GrossAmount, PayDate, PayRef,PayRefNo, PayType,
PayAmount, Curr, GBPNetAmount, GBPVATAmount, GBPGrossAmount, NetAmountAbs, GrossAmountAbs, VATAmountAbs, DocType, SuppInvNoNums, VATPerc, VATA, VATB, VATC,
VATD, VATE, VATPotentialClaim, ClaimStatus, SuppInvNoSubst, SuppInvNoSubstFlag, DupeSubstGross, DupeSubstNet, SuppInvNoCharMap, SuppInvNoCharMapFlag, SeqErrFlag)
SELECT
FK_SysInvoiceID,
CONCAT(CTE.NetAmountAbs, CTE.AccountNumber),
Netted,
InvoiceNo,
InvoiceDate,
I.FK_SupplierID,
SuppInvNo,
NetAmount,
VATAmount,
GrossAmount,
PayDate,
PayRef,
PayRefNo,
PayType,
PayAmount,
Curr,
GBPNetAmount,
GBPVATAmount,
GBPGrossAmount,
CTE.NetAmountAbs,
GrossAmountAbs,
VATAmountAbs,
DocType,
SuppInvNoNums,
VATPerc,
VATA,
VATB,
VATC,
VATD,
VATE,
VATPotentialClaim,
ClaimStatus,
SuppInvNoSubst,
SuppInvNoSubstFlag,
DupeSubstGrs,
DupeSubstNet,
SuppInvNoCharMap,
SuppInvNoCharMapFlag,
SeqErrFlag
FROM (SELECT
FK_SupplierID,
AccountNumber,
NetAmountAbs,
CASE WHEN MIN(NetAmountAbs) < SUM(NetAmount) THEN 0 ELSE -1 END AS Netted
FROM invoice
WHERE NetAmountAbs >= 500 and InvoiceDate IS NOT null
GROUP BY FK_SupplierID,
NetAmountAbs
HAVING COUNT(*) > 1
AND ((SUM(CASE WHEN NetAmount >= 0 THEN 1 ELSE 0 END)) > 1)
AND (MAX(SuppInvNoNums) != MIN(SuppInvNoNums))
AND (MIN(InvoiceDate) != MAX(InvoiceDate))
AND (DATE_SUB(MAX(COALESCE(InvoiceDate, NOW())) <= MIN(COALESCE(InvoiceDate, NOW())), INTERVAL 30 DAY))
AND (MAX(GrossAmountAbs) != MIN(GrossAmountAbs))) CTE
INNER JOIN invoice I
ON CTE.NetAmountAbs = I.NetAmountAbs
AND CTE.FK_SupplierID = I.FK_SupplierID
ORDER BY CTE.NetAmountAbs DESC, CTE.FK_SupplierID;
它从表中获取,执行一些计算,连接自身,然后插入.它失败并显示以下消息:Incorrect DateTime Value '0000-00-00 00:00:00'
.我已经缩小了范围,如果我从有条款中删除这一行 (DATE_ADD(MAX(COALESCE(InvoiceDate, NOW())) <= MIN(COALESCE(InvoiceDate, NOW())), INTERVAL -30DAY))
有效.
It takes from a table, performs some calculations, joins on itself and then inserts. It failed with this message: Incorrect DateTime Value '0000-00-00 00:00:00'
. I have narrowed it down and if I remove this line from the having clause (DATE_ADD(MAX(COALESCE(InvoiceDate, NOW())) <= MIN(COALESCE(InvoiceDate, NOW())), INTERVAL -30 DAY))
it works.
事实上,当我奇怪地移除插入物时它会起作用.
In fact, it works when I remove the insert strangely.
选择没有返回任何内容,但仍然失败.
The select doesn't return anything yet it still fails.
这是为什么?谁能帮忙找出原因?
Why is this? Can anyone help find out why?
推荐答案
第一个选项:
这个警告可能是由于 SQL_MODE
.
This warning probably could be due to the SQL_MODE
.
根据 mysql 文档如果启用了 NO_ZERO_DATE 或 NO_ZERO_IN_DATE SQL 模式,则不允许零日期或部分日期.".所以这可能是你的 INSERT
with '0000-00-00 00:00:00' 失败的原因.
According to mysql documentation "If the NO_ZERO_DATE or NO_ZERO_IN_DATE SQL mode is enabled, zero dates or part of dates are disallowed.". So this may be the cause your INSERT
with '0000-00-00 00:00:00' fails.
您可以通过执行以下命令检查您的 sql 模式:
You can check your sql mode by executing this:
SELECT @@sql_mode;
如果设置了任何 NO_ZERO_DATE
或 NO_ZERO_IN_DATE
,那么您可以:
and if any of the NO_ZERO_DATE
or NO_ZERO_IN_DATE
are set, then you can just:
SET sql_mode = '';
第二个选项
另一个选项是由于 STRICT_TRANS_TABLES
模式而失败.正如mysql文档所说:
The other option is it is failing because of the STRICT_TRANS_TABLES
mode.
As mysql documentation say:
严格模式影响服务器是否允许 '0000-00-00' 作为有效date:如果未启用严格模式,则允许使用0000-00-00"并且插入不会产生警告.如果启用严格模式,则0000-00-00"为不允许并且插入会产生错误,除非 IGNORE 给出为好.对于 INSERT IGNORE 和 UPDATE IGNORE,允许使用0000-00-00"并且插入会产生警告
Strict mode affects whether the server permits '0000-00-00' as a valid date: If strict mode is not enabled, '0000-00-00' is permitted and inserts produce no warning. If strict mode is enabled, '0000-00-00' is not permitted and inserts produce an error, unless IGNORE is given as well. For INSERT IGNORE and UPDATE IGNORE, '0000-00-00' is permitted and inserts produce a warning
同样适用于日期时间.
因此,您必须禁用 STRICT MODE 或,如果禁用它不是一个选项 - 修改查询,使其不会返回无效的日期/日期时间结果
So you have to either disable STRICT MODE OR if disabling it is not an option - modify the query so it doesn't return invalid date/datetime result
这篇关于不正确的日期时间值 '0000-00-00 00:00:00' - Date_Sub() 在有的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!